Question

PLEASE HELP

Answer 1

Answer:

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

Explanation:

$2Mg+O_2\rightarrow 2MgO$

Mass of oxygen gas = 4.63 g

Moles of oxygen gas = $\frac{4.63 g}{32 g/mol}=0.145 mol$

According to reaction,  1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:

$\frac{2}{1}\times 0.145 mol=0.29 mol$ of magnesium oxide

Mass of 0.2894 moles of magnesium oxide:

= 0.29 mol × 40 g/mol = 11.6 g

11.6 grams of MgO can be produced with 4.63 grams of oxygen.