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kramer
3 years ago
8

PLEASE HELP

Chemistry
1 answer:
Vinvika [58]3 years ago
5 0

Answer:

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

Explanation:

2Mg+O_2\rightarrow 2MgO

Mass of oxygen gas = 4.63 g

Moles of oxygen gas = \frac{4.63 g}{32 g/mol}=0.145 mol

According to reaction,  1 mole of oxygen gas gives 2 moles of magnesium oxide, then 0.1447 moles of oxygen gas will giv e:

\frac{2}{1}\times 0.145 mol=0.29 mol of magnesium oxide

Mass of 0.2894 moles of magnesium oxide:

= 0.29 mol × 40 g/mol = 11.6 g

11.6 grams of MgO can be produced with 4.63 grams of oxygen.

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Which of the following molecules experience dipole-dipole forces as its strongest IMF? A) H2 B) SO2 C) NH3 D) CF4 E) BCl3
Xelga [282]

Answer: NH_3

Explanation:

a) H_2: This  is a non polar covalent compound which are held by weak vanderwaal forces of attraction.

b) SO_2: This  is a covalent compound which is polar due to the presence of lone pair of electrons and are held by dipole-dipole forces of attraction.

c) NH_3: These are joined by a special type of dipole dipole attraction called as hydrogen bond. It forms between electronegative nitrogen atom and hydrogen atom and is the strongest interaction.

d) CF_4: This  is a covalent compound and is non polar which are held by weak vanderwaal forces of attraction.

e)  BCl_3: This  is a covalent compound and is non polar which are held by weak vander waal forces of attraction.

5 0
3 years ago
What is the mass number of an atom that contains 85 protons 133 neutrons and 85 electrons​
Vikentia [17]
The mass would be the sum of the protons and neutrons. Your answer would be 218
6 0
3 years ago
A 90.00 mL solution of NaCl and ethyl alcohol has 7.83 g of salt dissolved in the alcohol. Calculate the molar concentration of
nalin [4]
The  molar  concentration  of the solution  is calculated as  follows

find the moles of NaCl used  to  make the solution

moles =  mass/molar  mass
mass =7.83  g
molar  mass =58.5  g/mol
moles = 7.83 g/ 58.5 g/mol = 0.134 moles

molarity (  concentration  in mol/l) =  number  of moles/volume  in  liters

volume  in liters =  90ml/1000 =0.09  liters

molarity  is  therefore = 0.134  moles/0.09 L =1.49   M


8 0
3 years ago
Read 2 more answers
Listed below are the amounts of mercury​ (in parts per​ million, or​ ppm) found in tuna sushi sampled at different stores. The s
LenaWriter [7]

Answer:

• <em>The 90%  inverval estimate of the mean amount of mercury in the population is </em><u>[0.420 ppm, 1.252 ppm]</u>.

Explanation:

<u>1) Data:</u>

• μ = 0.836 ppm

• σ = 0.253 ppm

• z = ?

• 90% confidence interval estimate of the mean = ?

<u />

<u>2)  Finding Zo for Pr = 90%</u>

The symmetry of the standard normal distribution implies that, for the 90% confidence interval, 5% of the values (area) are above Zo and 5% are below = - Zo.

Using <em>technology</em> (statistic software) or a <em>table</em> of the standard normal probability, you find that for Pr ≥ 0.05 means Zo   ≥ 1.6045.

And, by symmetry, Pr ≤ 0.05 means Zo ≤ -1.6045.

<u>3) Calculate the limits of the interval:</u>

<u />

• Formula:  z = ( X - μ) / σ

• Upper limit:  X = zσ + μ = 1.645 (0.253 ppm) + 0.836 ppm = 1.252 ppm.

• Lower limit: X = zσ + μ = -1.645 (0.253ppm) + 0.836 =  0.420 ppm.

Then, the 90%  inverval estimate of the mean amount of mercury in the population is [0.420 ppm, 1.252 ppm] ← answer

3 0
3 years ago
You find that 7.36g of a compound has decomposed to give 6.93g of oxygen. The only other element is hydrogen. If the molar mass
OleMash [197]

Answer:

The molecular formula of this compound is H_{2}O_{2}

Explanation:

From the given,

Mass of compound = 7.36 g

Molar mass of compound = 34.0 g/mol

The mass of oxygen = 6.93 g

The hydrocarbon contains only hydrogen and carbon.

Mass of hydrogen + Mass of oxygen = 7.36 g

Mass of hydrogen + 6.93 g = 7.36 g

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Molar mass of hydrogen = 1.0 g/mol

Molar mass of oxygen = 16 g/mol

Number\,of\,moles\,of \,Oxygen=6.93g\times\frac{1}{16}=0.43mol

Number\,of\,moles\,of \,hydrogen=0.43g\times\frac{1}{1}=0.43mol

Now divided each one by 0.43

Oxygen:

\frac{0.43}{0.43}=1

Hydrogen :

\frac{0.43}{0.43}=1

6 0
3 years ago
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