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Aleonysh [2.5K]
4 years ago
8

One mole of ANY element contains the:

Chemistry
1 answer:
NeTakaya4 years ago
8 0
Not sure, just setting up account
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A 3.664 g sample of a monoprotic acid was dissolved in water. It took 20.27 mL of a 0.1578 M NaOH solution to neutralize the aci
chubhunter [2.5K]

Answer:

Molar mass of monoprotic acid is 1145g/mol.

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The reaction of a monoprotic acid (HX) with NaOH is:

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If the neutralization of the acid spent 20.27mL of a 0.1578 M NaOH solution. Moles of NaOH are:

0.02027L × (0.1578mol / L) = <em>3.199x10⁻³ moles</em> NaOH ≡ moles HX.

As mass of the sample is 3.664g, molar mass of the acid is:

3.664g / 3.199x10⁻³ moles =<em> 1145g/mol</em>

5 0
4 years ago
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