The best answer is 107 degrees. The nitrogen atom in ammonia is surrounded by three bonding pairs and one lone pair of electrons giving a shape of a tetrahedron. The bond angle is 107 degrees which is less than the tetrahedral bond angle.
Answer:
V = 15.2 L
Explanation:
STP means that T = 273 K and P = 1 atm.
We use the<em> PV=nRT equation</em> to <u>convert the given liters of oxygen to moles</u>:
- 1 atm * 7.6 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
Now we<u> convert O₂ moles to H₂O moles</u>, using the <em>stoichiometric coefficients</em> of the equation:
- 0.340 mol O₂ * = 0.68 mol H₂O
Finally we use the PV=nRT equation once again to<u> convert 0.68 moles of H₂O to liters</u>:
- 1 atm * V = 0.68 * 0.082 atm·L·mol⁻¹·K⁻¹ * 273 K
Answer: The answer is element
Hope this helps and please brainliest and ty
There would be four to five atoms left
The amount of heat that could be removed by 20.0 g of ethyl chloride is 8.184 kJ.
<h3>How do we calculate required heat?</h3>
Required amount of heat which can be removed for the vaporization will be calculated as:
Q = (n)(ΔHv), where
- n = moles of ethyl chloride
- ΔHv = heat of vaporization = 26.4 kj/mol
Moles will be calculated as:
n = W/M, where
- W = given mass of ethyl chloride = 20g
- M = molar mass of ethyl chloride = 64.51 g/mol
n = 20 / 64.51 = 0.31 mol
On putting all these values in the above equation, we get
Q = (0.31)(26.4) = 8.184 kJ
Hence involved amount of heat is 8.184 kJ.
To know more about heat of vaporization, visit the below link:
brainly.com/question/13106213
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