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3 years ago

A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example?

Physics

2 answers:

amid [387]3 years ago

8 0

Negative force is the answer

scZoUnD [109]3 years ago

4 0

This would be a negative force because they are going in different directions

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t= d / v
= 2 / 100
= 0.02sec

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3 years ago

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melomori [17]

Answer:

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Explanation:

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3 years ago

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3 years ago

Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the

leonid [27]

Answer:

$KE_A=33\ J$

$KE_B=99\ J$

Explanation:

Given:

Let mass of the particle B be, $m_B=m$

then the mass of particle A, $m_A=3m$

Energy stored in the compressed spring, $E=132\ J$

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

$\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132$

$3m.v_A^2+m.v_B^2=264$ .............................(1)

Using the conservation of linear momentum:

$m_A.v_A+m_B.v_B=0$

$3m.v_A+m.v_B=0$ .............................(2)

Put the value of $v_A$ from eq. (2) into eq. (1)

$3m\times (\frac{-v_B}{3})^2+m.v_B^2=264$

$v_B^2=\frac{198}{m}$ ...........................(3)

Now the kinetic energy of particle B:

$KE_B=\frac{1}{2}\times m_B\times v_B^2$

$KE_B=\frac{1}{2}\times m\times \frac{198}{m}$

$KE_B=99\ J$

Put the value of $v_B^2$ form eq. (3) into eq. (1):

$v_A^2=\frac{22}{m}$

Now the kinetic energy of particle A:

$KE_A=\frac{1}{2}m_A.v_A^2$

$KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}$

$KE_A=33\ J$

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3 years ago