The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
To find the answer, we have to know about the focal length of correcting lens.
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How to find the focal length of
correcting lens?</h3>
- If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,
- It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,
Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
Learn more about the focal length here:
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The height of the projectile is given by:
h = ut - 0.5at²
The height will be 0 twice, once at t = 0 and the second time at the time when the journey has been completed, or t = hang time.
0 = 7.3t - 0.5(9.81)t²
t = 1.49 seconds
Answer:
303.975kPa
0.933kPa
0.099atm
112.509mmHg
Explanation:
Remember your conversions first so you can do this:
1 atm = 101.325 kPa
1 atm = 760 mmHg
A good pattern to remember when you are converting is always put what you want to convert into on top and the what you want to cancel out under. (I hope this makes sense).
1. 3.0000 atm → kPa
See how I placed atm at the bottom to cancel them out?
2. 7.000mmHg → kPa
For this problem, we will convert twice. First mmHg to atm, then atm to kPa.
Although, you can do this directly by getting the conversion value of mmHg to kPa, this can make things more difficult to do because the value is small.
3. 10.00kPa → atm
Like in the first problem this is a direct conversion.
4. 15.00 kPa → mmHg
Here we do another double conversion:
Answer:
Inertia! I hope this helps!
Answer:
x = 45 [m]
Explanation:
To solve this problem we must use the following kinematics equation:
where:
Vf = final velocity = 0
Vi = initial velocity = 15 [m/s]
a = desacceleration = 2.5 [m/s^2]
x = distance [m]
Note: the negative sign in the equation above, is because the car slows down.
0^2 = 15^2 - (2*2.5*x)
2*2.5*x = 15^2
x = 45 [m]