Answer:
Explanation:
Force, F = 12 N
distance, s = 16.4 m
time, t = 2.5 s
initial velocity, u = 0 m/s
Let a be the acceleration
use second equation of motion
s = ut + 1/2 at²
16.4 = 0 + 0.5 x a x 2.5 x 2.5
a = 5.25 m/s²
Let m be the mass of the tool.
F = ma
12 = m x 5.25
m = 2.286 kg
Now for vertical motion
h = 10.3 m
u = 0 m/s
t = 2.88 m/s²
Let the acceleration due to gravity on that planet is g'
Use second equation of motion
10.3 = 0 + 0.5 x g' x 2.88 x 2.88
g' = 2.485 m/s²
Let W' be the weight of the tool on that planet
W' = m g' = 2.286 x 2.485 = 5.68 N
Let W be the weight of the tool on the earth
W = m x g = 2.286 x 9.8 = 22.4 N