Question

A person having a mass of 85 kg sits on the edge of a horizontal rotating platform, 2.2 m from the center of the platform, and has a tangential speed of 6.6 m/s. calculate the angular momentum of the person

Answer 1

The angular momentum of the person is given by:
$L=mvr$
where $m=85 Kg$ is the mass of the person, $v=6.6 m/s$ is the tangential velocity, and $r=2.2 m$ is the distance of the person from the center of rotation. Using these data, we find
$L=(85 Kg)(6.6 m/s)(2.2 m)=1234.2 Kg \cdot m^2/s$