A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater
than atmospheric pressure? The density of glycerine is 1.26X10^3 kg/m^3
1 answer:
Answer:
So, at the depth of 24 cm below the surface of the glycerine the pressure is 2970 Pa. Hence, this is the required solution.
Explanation:
Given that,
Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.
The density of glycerine,
We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :
h = 0.24 meters
or
h = 24 cm
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