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2 years ago

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A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater

than atmospheric pressure? The density of glycerine is 1.26X10^3 kg/m^3

1 answer:

Mice21 [21]2 years ago

5 0

Answer:

So, at the depth of 24 cm below the surface of the glycerine the pressure is 2970 Pa. Hence, this is the required solution.

Explanation:

Given that,

Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.

The density of glycerine,

We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :

h = 0.24 meters

or

h = 24 cm

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From the question we are told that

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Generally the equation Pythagoras theorem is given mathematically by

$c^2=a^2+b^2$

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b)Resultant direction

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