Element X is in Group 2 and element Y is in Group 17. A compound formed between these two elements is most likely to have the fo
2 answers:
Answer: The correct option is B.
Explanation: We are given that Element X is present in Group 2, so its valence electronic configuration will be: . It will loose 2 electrons in order to attain stable electronic configuration.
Element Y is present in Group 17, so its valence electronic configuration is: .It will gain 1 electron to attain stable electronic configuration.
Hence, we can say that 2 atoms of Y-element will be required to combine with 1 atom of X-element.
Therefore, the formula becomes .
You might be interested in
Answer: 0.156 mol
Explanation:
To find the moles of 17.2 g K₂S, we need to know the molar mass to convert.
<u>Answer:</u> The mass of iron (III) chloride produced is 14.81 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For iron(III) oxide:</u>
Given mass of iron(III) oxide = 10.0 g
Molar mass of iron(III) oxide = 159.7 g/mol
Putting values in equation 1, we get:
- <u>For hydrochloric acid:</u>
Given mass of hydrochloric acid = 10.0 g
Molar mass of hydrochloric acid = 36.5 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of iron (III) oxide and hydrochloric acid follows:
By Stoichiometry of the reaction:
6 moles of hydrochloric acid reacts with 1 mole of iron (III) oxide
So, 0.274 moles of hydrochloric acid will react with = of iron (III) oxide
As, given amount of iron (III) oxide is more than the required amount. So, it is considered as an excess reagent.
Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
6 moles of hydrochloric acid produces 2 moles of iron (III) chloride
So, 0.274 moles of hydrochloric acid will produce = of iron (III) chloride
Now, calculating the mass of iron (III) chloride from equation 1, we get:
Molar mass of iron (III) chloride = 162.2 g/mol
Moles of iron (III) chloride = 0.0913 moles
Putting values in equation 1, we get:
Hence, the mass of iron (III) chloride produced is 14.81 grams