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Ray Of Light [21]
3 years ago
12

With what minimum speed must athlete leave the ground in order to lift his center of mass 1.80 m and cross the bar with a speed

of 0.65 m/s ?
Physics
1 answer:
tatiyna3 years ago
3 0

Answer:

The minimum velocity is V=5.98[m/s]

Explanation:

In this problem the athlete jumps by printing a force to raise his mass at an initial speed, which we must determine. These two initial amounts of energy that we have, the kinetic energy (velocity with which it jumps) and the work done (mass of the athlete by the jumped distance) must be equal to the kinetic energy when its velocity is equal to 0.65[m/s]. By raising this equation, the initial speed can be cleared.

We have to keep in mind that the weight is acting down and the movement is one up so the work done by the force is negative

Therefore we have:

Ek1+W=Ek2\\where\\Ek1= initial kinetic energy\\W= work done\\Ek2=final kinetic energy

\frac{1}{2} *m*v_{0} ^{2} - (m*g*h)=\frac{1}{2}  *m*v_{f} ^{2} \\

Reorganizing each of the members of the equation and clearing the final velocity.

v_{0} =\sqrt{(v_{f})^{2} +2*g*h} \\v_{0} =\sqrt{(0.65)^{2} +2*9.81*1.8} \\v_{0} =5.98[m/s)

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Explain Energy Transformation using the image below and how the Law of Conservation of Energy is maintained.
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The chemical energy of petrol is converted to heat energy on combustion. The heat energy is converted to kinetic energy by the use of internal combustion engines in vehicles. The law of conservation of energy is maintained in each process.

<h3>What is kinetic energy?</h3>

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K.E = 1/2 mv²

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8 0
2 years ago
You illuminate the grating in a spectrometer at normal incidence θi=0° with a beam of light that has a wavelength of 6562.8 Å. T
monitta

Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

     d sin θ = m λ

Where is the distance between lines, λ is the wavelength and m is the order of the spectrum

The distance between one lines, we can find used a rule of proportions

     d = 1/600

     d = 1.67 10⁻³ mm

    d = 1-67 10⁻³ m

Let's calculate the angle

    sin θ = m λ / d

    θ  = sin⁻¹ (m λ / d)

First order

    θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)

    θ₁ = sin⁻¹ (3.93 10⁻¹)

    θ₁ = 23.14 °

Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

     θ₂ = sin⁻¹ (0.786)

     θ₂ = 51.81 °

3 0
3 years ago
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