Answer:
The velocity and height is 31 m/s and 44.4 m respectively .
Explanation:
Given :
Initial speed of rock , u = 8.5 m/s .
Time taken to reach ground , t = 2.25 s .
Also , acceleration due to gravity is , .
Now , to find the velocity when it hit ground .
Applying equation of motion :
Also , height from which rock is thrown is given by :
Hence , this is the required solution .
Answer:
a) Acceleration of the car is given as
b) Acceleration of the truck is given as
Explanation:
As we know that there is no external force in the direction of motion of truck and car
So here we can say that the momentum of the system before and after collision must be conserved
So here we will have
now we have
a) For acceleration of car we know that it is rate of change in velocity of car
so we have
b) For acceleration of truck we will find the rate of change in velocity of the truck
so we have
Wire rope guardrails are supposed to be capable of withstanding a force of 200 pounds without failure, it must not deflect under pressure to less than 39 inches above the walking surface, and it must be at least a quarter inch in thickness to prevent cuts when installing around buildings. To install the metal guardrail safely, you must use a sufficient amount of clips on the wire to ensure that it will not snap under the pressure and to ensure that it is safe to walk on or use as a support.
Answer:
-0.01N
Explanation:
I'm assuming you're asking for the net force of the paper.
0.01N - 0.02N = -0.01N
Answer:
11.16 J
Explanation:
Elastic energy (E) stored in the tendon is given by 1/2ke^2
SPRINTERS
k = 31N/mm = 31N/mm × 1000mm/1m = 31,000N/m
e = 41mm = 41mm × 1m/1000mm = 0.041m
E = 1/2 × 31,000 × 0.041^2 = 26.06J
NON-ATHLETES
k = 31,000N/m
e = 31mm = 31mm × 1m/1000 = 0.031m
E = 1/2 × 31,000 × 0.031^2 = 14.90 J
Difference = 26.06 J - 14.90 J = 11.16 J