Question

A wire along the z axis carries a current of 6.4 A in the z direction Find the magnitude and direction of the force exerted on an 8.0 cm long length of the wire by a uniform magnetic field with magnitude 0.50 T in the x direction

Answer 1

Answer:

The magnetic force will be 0.256 N in +y direction.                                          

Explanation:

It is given that, a wire along the z axis carries a current of 6.4 A in the z direction. Length of the wire is 8 cm. It is placed in uniform magnetic field with magnitude 0.50 T in the x direction.

The magnetic force in terms of length of wire is given by :

$F=I(L\times B)\\\\F=ILB\\\\F=6.4\times 0.08\times 0.5\\\\F=0.256\ N$

For direction,

$F=I k(L\times Bi)\\\\F=Fj$

So, the magnetic force will be 0.256 N in +y direction.