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olchik [2.2K]
3 years ago
10

Choosing to purchase which of the following is likely most harmful to orangutans? Chocolate spreads that contain palm oil. Cold

remedies that contain eucalyptus. Gloves that contain latex. Hand sanitizers that contain lemon oil.
Engineering
2 answers:
Ksju [112]3 years ago
5 0

Answer:

The answer is Chocolate spread that contain palm oil.

Explanation:

Based on research, it is estimated that between 1,000 to 5,000 orangutans are killed in Palm Oil concessions.

xenn [34]3 years ago
3 0

The correct answer is A. Chocolate spreads that contain palm oil.

Explanation:

Palm oil is a type of edible oil that is used in multiple products including ice cream, chocolate, cookies, among others. The use of this type of oil has had a great negative impact on the environment because due to its popularity and extensive forest are completely cleared to cultivate oil palms. This leads to the destruction of trees and the animal species living on them; one of these species is orangutan because the population of orangutans in regions such as Indonesia due to the cultivation of oil palms has reduced dramatically.

According to this, it is purchasing chocolate spreads that contain palm oil the one that is most harmful to orangutans because this supports the cultivation of oil palms to extract palm oil used in the chocolate and therefore indirectly supports the destruction of forests where orangutans live.

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\mathbf{h_2 =1021.9 \  mm}

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At temperature T_2 = 70^0 C  the density of the water is \rho = 977.8 \ kg/m^3

The mass of the water is  \rho V = \rho _1 V_1 = \rho _2 V_2

Thus; we can say \rho _1 V_1 = \rho _2 V_2;

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V_2 = \dfrac{999.7 \ kg/m^3*1000 \ mL}{977.8 \ kg/m^3 }

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However; taking an integral look at this process; the volume of the water before heating can be deduced by the relation:

V_1 = A_1 *h_1

The area of the water before heating is:

A_1 = \dfrac{V_1}{h_1}

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A_1 = 1000 \ mm^2

The area of the heated water is :

A_2 = A_1 (1  + \Delta t  \alpha )^2

A_2 = A_1 (1  + (T_2-T_1) \alpha )^2

A_2 = 1000 (1  + (70-10) 3.8*10^{-6} )^2

A_2 = 1000.5 \ mm^2

Finally, the depth of the heated hot water is:

h_2 = \dfrac{V_2}{A_2}

h_2 = \dfrac{1022400}{1000.5}

\mathbf{h_2 =1021.9 \  mm}

Hence the depth of the heated hot  water is \mathbf{h_2 =1021.9 \  mm}

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