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4 years ago

9

huge loops or sheets of gas erupting from active regions around sunspots. These features arch into the Sun's atmosphere and conn

ect pairs of sunspots.

2 answers:

Sunny_sXe [5.5K]4 years ago

5 0

PROMINENCES THATS THE ANSWERS

hammer [34]4 years ago

5 0

Answer:

prominences

Explanation:

i did it on study island

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A 0.453 kg pendulum bob passes through the lowest part of its path at a speed of 2.58 m/s. What is the tension in the pendulum c

harkovskaia [24]

Answer with Explanation:

Mass of pendulum bob, m=0.453 kg

Speed, $v_1=$ 2.58 m/s

a.r=75.1 cm= $75.1\times 10^{-2}m$ =0.751 m

$1cm=10^{-2} m$

Tension in the pendulum cable is given by

Tension=Centripetal force+force due to gravity

$T=\frac{mv^2}{r}+mg$

Where $g=9.8 m/s^2$

Substitute the values

$T=\frac{0.453(2.58)^2}{75.1\times 10^{-2}}+0.453\times 9.8$

$T=8.45 N$

b.When the pendulum reaches its highest point,then

Final velocity, $v_2=0$

According to law of conservation of energy

$mgh_1+\frac{1}{2}mv^2_1=mgh_2+\frac{1}{2}mv^2_2$

$gh_1+\frac{1}{2}v^2_1=gh_2+\frac{1}{2}v^2_2$

$h_1=0$

Substitute the values

$9.8\times 0+\frac{1}{2}(2.58)^2=9.8\times h_2+\frac{1}{2}(0)^2$

$3.3282=9.8h_2$

$h_2=\frac{3.3282}{9.8}=0.34 m$

The angle mad by cable with the vertical= $cos\theta=\frac{0.751-0.34}{0.751}=0.55$

$\theta=cos^{-1}(0.55)=56.6^{\circ}$

c.When the pendulum reaches at highest point then

Acceleration, a=0

Therefore, the tension in the pendulum cable

$T=mgcos\theta$

Substitute the values

$T=0.453\times 9.8cos56.6$

$T=2.4 N$

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3 years ago

What is Potentiometer

Katena32 [7]

Answer:

an instrument for measuring an electromotive force by balancing it against the potential difference produced by passing a known current through a known variable resistance.

3 0

3 years ago

The coefficient of linear expansion of iron is 1.0 × 10−5 per C◦ . The surface area of an iron cube, with an edge length of 5.0

Allushta [10]

The linear expansion of iron is a = 1× 10∧ -5 /°C
Length edge is 5cm
Initial surface area of cube A = 6L ∧²
= 150cm∧²
The edge length of cube after being heated from
10°C to 60°C is
L = L[I +a dt] where the dt is = 60-10 = 50°C
5.0025cm
A surface area of the cube after heated is
A' = 6L' ∧²
= 150.1500375 cm∧²
The increased area is = A' -A = 0.15cm∧²

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3 years ago

Two small space probes have been slowed to 10m/s as they approach the moon from the same direction. Probe 1 has a mass of 86kg a

bulgar [2K]

Answer:

B

Explanation:

B

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3 years ago

bekas [8.4K]

They can pretty much be by water i think

5 0

3 years ago