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lana66690 [7]
3 years ago
7

Examples of forces in motion that you can see?

Physics
1 answer:
lidiya [134]3 years ago
6 0

Answer:

tensional force

Explanation:

It usually exist in fluid or any liquid substance where by an object is put before it

e.g An ant can walk on water without submersed in it.

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A tank with a flat bottom is filled with water to a height of 7.5 meters. What's the pressure at any point at the bottom of the
Ivanshal [37]
<h3>Answer:</h3>
  • p=75 kPa
<h3>Explanation:</h3>

_______________

h=7,5 m

g=10 m/s²

ρ=1000 kg/m³

_______________

p - ?

_______________

p=ρgh=1000 kg/m³ · 10 m/s² · 7,5 m = 75000 Pa = 75 kPa

5 0
2 years ago
Find the approximate value of the circumference of a circle with the given radius. Use π = 3.14. Round your results to one more
lara [203]
In order to find the circumference of a circle you need to use the equation C=2πr.
3 0
4 years ago
Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planc
Viefleur [7K]

In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
                                 E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

                                 E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

                                    = <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>


5 0
3 years ago
A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed
Lyrx [107]

Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.

In the free body diagram for the 500 N weight, we have a figure Y with the net force equations

• horizontal net force:

∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0

• vertical net force:

∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0

From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have

2 T sin(θ) = 500 N

and if the maximum permissible tension is T = 1800 N, it follows that

sin(θ) = (500 N) / (3600 N)   ⇒   θ = arcsin(5/36) ≈ 7.9°

is the smallest angle the rope can make with the horizontal.

6 0
3 years ago
The joule and the kilowatt-hour are both units of energy. 15 kw · h is equivalent to how many joules? answer in units of j.
choli [55]

The solution for the problem is:

1 Watt = 1 Joule per second 
1 Watt*second = 1 Joule 

a Kilowatt is 1,000 Watts 
an hour is 60 seconds times 60 minutes or 3,600 seconds 
a Kilowatt * hour is 1,000 Watts in 3,600 seconds 

15 W*h = 15,000 Watt*hour = 15,000 Watt * 3,600 seconds = 54,000,000 Watt*second 

54,000,000 Watt*second = ? Joules 
54,000,000 Joules / second = 54,000,000 Watts

3 0
4 years ago
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