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yawa3891 [41]
3 years ago
10

N=4 has how many orbitals?

Chemistry
1 answer:
marin [14]3 years ago
5 0

Answer:

n = 4 there are 16 orbitals

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Can someone help me with these. I don’t understand how to answer them or do the work
ICE Princess25 [194]
How am I supposed to help you if there's not picture of what the problem is
6 0
3 years ago
What best describes the bonding in a carbon dioxide molecule?
gogolik [260]

Answer:

B. Carbon shares 2 pair of electrons with each oxygen.

Explanation:

  • Carbon dioxide is formed from combustion reactions, which involves a reaction between carbon and oxygen gas.
  • Carbon dioxide molecule is formed from one carbon atom and two oxygens. As an element, carbon only has 4 outer shell electrons and oxygen 6.
  • The two atoms require to gain electrons to achieve a stable configuration; carbon require to gain four electrons and oxygen requires two electrons.
  • Double covalent bonds form between the atoms, where two electrons from each atom are shared making 4 bonding electrons in total.

Hope it helped!

6 0
3 years ago
Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equat
Alex

6.069 grams is the  mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid.

Explanation:

Balanced equation for the reaction:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

data given:

mass of aluminum = 27 grams

atomic mass of one mole of aluminum = 26.89 grams/mole

formula to calculate number of moles:

number of moles = \frac{mass}{atomic mass of one mole}

number of moles = \frac{27}{26.89}

                              = 1.004 moles of aluminum will react

from the balanced equation:

2 moles of Al reacted to form 3 moles of H2

1.004 moles of Al will produce x moles of H2

\frac{3}{2} = \frac{x}{1.004}

x = 3.012 moles of H2 will be formed.

mass will be calculated as number of moles multiplied by atomic weight

mass of 3.012 moles of hydrogen ?(atomic weight of one mole H2 = 2.015 grams)

= 3.012 x 2.015

= 6.069 grams of H2 will be formed.

6 0
3 years ago
100 cm3 of the copper sulfate solution contains 1.8 g of copper sulfate.
elixir [45]

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution  = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m  = 25×0.018 g = 0.45 g

∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g

8 0
3 years ago
Hii pls help me to balance the equation and state the symbols thanksss​
velikii [3]

Answer:

I DID HOW I KNOW . I HOPE IT WILL HELP YOU :D

8 0
3 years ago
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