Question

What is the change in internal energy if 60 J of heat is released from a system and 30 J of work is done on the system? Use U = Q - W.
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Answer 1

The change in internal energy of the system is +30 J

Explanation:

We can solve this problem by using the first law of thermodynamics, which states that the change in internal energy of a system is given by the equation:

$\Delta U = Q -W$

where

$\Delta U$ is the change in internal energy

Q is the heat absorbed by the system (positive if it is absorbed, negative if it is released)

W is the work done by the system (positive if it is done by the system, negative if it is done by the surroundings on the system)

Therefore, in this problem, we have

$Q=-60 J$ (heat released by the system)

$W=-30 J$ (work done on the system)

Therefore, the change in internal energy is

$\Delta U = -60 - (-30) = +30 J$

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