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shutvik [7]
3 years ago
11

A 15-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 23 n. starting from rest, the sle

d attains a speed of 1.8 m/s in 8.5 m. find the coefficient of kinetic friction between the runners of the sled and the snow.
Physics
1 answer:
jolli1 [7]3 years ago
5 0
We know the relationship between distance traveled and velocity obtained under acceleration a:
a=\frac{v^2}{2S}=\frac{1.8^2}{2\cdot8.5}=0.19\frac{m}{s^2}
We know from second Newtons law that net force acting on the object is proportional to its mass and acceleration:
F_n=ma
The net force acting on the sledge is:
F_p-F_f=ma\\
F_f=F_p-ma\\
\mu mg=F_p-ma\\
\mu=\frac{F_p-ma}{mg}\\
\mu=\frac{23-15\cdot0.19}{15\cdot 9.81}=0.14
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<em></em>

Explanation:

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P = 120^{2} /48 = <em>300 W</em>

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