<u>I'm pretty sure your answer is B, because Sequential Control operates during order like a schedule</u>
Sequential Control=A control system in which the individual steps are processed in a predetermined order, progression from one sequence step to the next being dependent on defined conditions being satisfied.
Tell me if I'm incorrect but, Hope this helps!
The level of strategy which the software engineers would concern themselves with would be highly dependent on the nature of the case or situation.
<h3>What is a strategy?</h3>
A strategy can be defined as a set of guiding principles, procedures, actions, and decisions that a business organization or an individual combines, in order to achieve its aim, objectives and goals.
Basically, developing a strategy is essential because it helps to attract new customers and gives a competitive advantage over rivals in the industry.
<h3>The types of
strategy.</h3>
In Software engineering, there are different types of strategy used by software engineers and these include:
- Product management strategy
- Lifecycle process strategy
Furthermore, there are three (3) main <u>levels</u> of strategy in software engineering and these are:
- Business-level strategy
- Functional-level strategy
- Corporate-level strategy
In this scenario, the level of strategy which the software engineers present at the meeting would concern themselves with would be highly dependent on the nature of the case or situation.
Read more on strategy here: brainly.com/question/26064163
Answer:
It is a type of ANOVA that can analyze several independent variables at the same time.
Explanation:
This is the statement that correctly describes the n-way analysis of variance (ANOVA). ANOVA is a type of analysis of variance that can analyze several independent variables at the same time. In this type of analysis, a dependent variable is measured by different levels of independent variables. When the results are obtained, these are assumed to be the consequence of the different levels of the independent variables, plus random error. The computation necessary for this analysis can be done in most types of statistical software.
Answer:
$$\begin{align*}
P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).
Explanation:
P(Y−X=m|Y>X)=∑kP(Y−X=m,X=k|Y>X)=∑kP(Y−X=m|X=k,Y>X)P(X=k|Y>X)=∑kP(Y−k=m|Y>k)P(X=k|Y>X).
Answer:
the MTTF of the transceiver is 50.17
Explanation:
Given the data in the question;
failure modes = 0.1 failure per hour
system reliability = 0.85
mission time = 5 hours
Now, we know that the reliability equation for this situation is;
R(t) = [ 1 - ( 1 - 
)³] 
so we substitute
R(5) = [ 1 - ( 1 - 
)³] 
= 0.85
[ 1 - ( 1 - 
)³] = 0.85
[ 1 - ( 0.393469 )³] = 0.85
[ 1 - 0.06091 ] = 0.85
0.9391 = 0.85
= 0.85 / 0.9391
= 0.90512
MTTF = 5 / -ln( 0.90512 )
MTTF = 50.17
Therefore, the MTTF of the transceiver is 50.17
