<h2>
Answer: The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths</h2>
Here we are talking about Diffraction and, in fact, waves diffract the most when their wavelength is about the same size of the gap or aperture.
Diffraction happens when a wave (mechanical or electromagnetic wave) meets an obstacle or a slit .When this occurs, <u>the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
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Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.
In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.
This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.
All of the above but normally in a triple beam
Answer:
<em>14.07 units of joules is removed for each joules of electricity used</em>
Explanation:
The heated room temperature
= 61 °F
The outside temperature
= 98 °F
For conversion from fahrenheit to kelvin we use the equation
(32°F − 32) × 5/9 + 273.15
= 289.26
= 309.82
For air conditioning,
COP =
COP =
= 14.07
This means that <em>14.07 units of joules is removed for each joules of electricity used</em>
Answer:
We conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.
Explanation:
Given
To determine
We need to find the quantity of the charge that flows through the wire in 50 s.
Important Tip:
A current of 1 Ampere = 1 Coulomb of charge flowing in 1 second
Using the formula involving charge and current

where:
represents the current in amperes (A)
represents the charge in coulomb (C)
represents the time in seconds (s)
now substituting I = 0.9 and t = 50 in the formula


switch sides

Multiply both sides by 50

Simplify
C
Therefore, we conclude that the quantity of the charge that flows through the wire in 50 s will be 45 C.