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NeX [460]
3 years ago
7

What is the energy difference between the states with the nuclear spin angular momentum components parallel and antiparallel to

the field?
Physics
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

Explanation:

The main difference is that states with spin angular momentum in the same direction of the field are more high energy that the states with antiparallel spin agular momentum.

The energy for a particular level is

E = -(γ*h/2*π)*m*B

where γ is a constant about magnetic moment, h is the Planck constant, m is the state level and B is the strength of the magnetic field. Its clear that for antiparallel spins m=-1/2 the energy is lower in comparisson with states with m=1/2

In fact

ΔE = γ*h*B/2*π

klemol [59]3 years ago
3 0

Answer:

Refer below for the explanation.

Explanation:

The principle distinction is that states with turn precise force a similar way of the field are all the more high vitality that the states with antiparallel turn agular energy.

E = - (γ*h/2*π)*m*B,

where γ is a consistent about attractive minute, h is the Planck steady, m is the state level and B is the quality of the attractive field. Plainly for antiparallel twists m=-1/2 the vitality is lower in comparisson.

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The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths.less for long wavelengths a
kompoz [17]
<h2>Answer: The spreading of waves behind an aperture ismore for long wavelengths and less for short wavelengths</h2>

Here we are talking about Diffraction and, in fact, waves diffract the most when their wavelength is about the same size of the gap or aperture.

Diffraction happens when a wave (mechanical or electromagnetic wave) meets an obstacle or a slit .When this occurs, <u>the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit. </u>

<u />

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.

This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.

6 0
3 years ago
Mass is measured using _____.
Gekata [30.6K]
All of the above but normally in a triple beam
8 0
3 years ago
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In a car factory, there are 8.0 assembly lines. Each assembly lines manufactures cars at the same speed. There are 12 workers wo
AlladinOne [14]

Answer: A

Explanation:

3 0
3 years ago
A Carnot air conditioner takes energy from the thermal energy of a room at 61°F and transfers it as heat to the outdoors, which
anyanavicka [17]

Answer:

<em>14.07 units of joules is removed for each joules of electricity used</em>

Explanation:

The heated room temperature T_{c} = 61 °F

The outside temperature T_{h} = 98 °F

For conversion from fahrenheit to kelvin we use the equation

(32°F − 32) × 5/9 + 273.15

T_{c} = 289.26

T_{h} = 309.82

For air conditioning,

COP = \frac{T_{c} }{T_{h} -T_{c} }

COP = \frac{289.26 }{309.82 -289.26 }  = 14.07

This means that <em>14.07 units of joules is removed for each joules of electricity used</em>

8 0
4 years ago
A wire in a circuit carries a current of 0.9 A. Calculate the quantity of
raketka [301]

Answer:

We conclude that the quantity of  the charge that flows through the wire in 50 s will be 45 C.

Explanation:

Given

  • Current I = 0.9 A
  • Time t = 50 s

To determine

We need to find the quantity of  the charge that flows through the wire in 50 s.

Important Tip:

A current of 1 Ampere = 1 Coulomb  of charge flowing in 1 second

Using the formula involving charge and current

I=\frac{Q}{t}

where:

  • I represents the current in amperes (A)
  • Q represents the charge in coulomb (C)
  • t represents the time in seconds (s)

now substituting I = 0.9 and t = 50 in the formula

I=\frac{Q}{t}

0.9\:=\:\frac{Q}{50}

switch sides

\frac{Q}{50}=0.9

Multiply both sides by 50

\frac{50Q}{50}=0.9\cdot \:50

Simplify

Q=45 C

Therefore, we conclude that the quantity of  the charge that flows through the wire in 50 s will be 45 C.

6 0
3 years ago
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