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NeX [460]
3 years ago
7

What is the energy difference between the states with the nuclear spin angular momentum components parallel and antiparallel to

the field?
Physics
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

Explanation:

The main difference is that states with spin angular momentum in the same direction of the field are more high energy that the states with antiparallel spin agular momentum.

The energy for a particular level is

E = -(γ*h/2*π)*m*B

where γ is a constant about magnetic moment, h is the Planck constant, m is the state level and B is the strength of the magnetic field. Its clear that for antiparallel spins m=-1/2 the energy is lower in comparisson with states with m=1/2

In fact

ΔE = γ*h*B/2*π

klemol [59]3 years ago
3 0

Answer:

Refer below for the explanation.

Explanation:

The principle distinction is that states with turn precise force a similar way of the field are all the more high vitality that the states with antiparallel turn agular energy.

E = - (γ*h/2*π)*m*B,

where γ is a consistent about attractive minute, h is the Planck steady, m is the state level and B is the quality of the attractive field. Plainly for antiparallel twists m=-1/2 the vitality is lower in comparisson.

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It took 1500 Newton's of force to push a car 3 meters. How much work was done
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2 years ago
Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what
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The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                     Q=\frac{\pi r^4P}{8\beta l}

  • where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
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Learn more about the Poiseuille's formula here:

brainly.com/question/13180459

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You make an observation that two objects attract. Which object below indicates the claim(s) that could be supported by this obse
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3 years ago
A charged particle accelerated to a velocity v enters the chamber of a mass spectrometer. The particle's velocity is perpendicul
gladu [14]

Answer:

Circle

Explanation:

When a charged particle is in motion in a region with magnetic field, the particle experiences a force whose magnitude is given by

F=qvB sin \theta

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

\theta is the angle between the directions of v and B

In this problem, the velocity of the particle is perpendicular to the magnetic field, so

\theta=90^{\circ}

and the formula reduces to

F=qvB

Also, the direction of this force is perpendicular to the direction of motion of the particle. This means that as the charge moves in the region of the magnetic field, the force acting on it acts as a centripetal force: therefore, the particle will start moving by unifom circular motion, with constant speed (because the magnetic force does no work on the particle, since it is perpendicular to the direction of motion).

So, the path of the particle will be a circle.

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