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koban [17]
3 years ago
15

An Olympic volleyball player spikes a 1.0 kg volleyball at a velocity of 20 m/s. What is the kinetic energy of the volleyball?

Physics
1 answer:
mylen [45]3 years ago
4 0
Pretty sure it’s 200
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A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
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Answer:

Explanation:

F = ma and

a=\frac{v}{t}

We have F, we have m, but in order to solve for v, we need a.

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6 0
2 years ago
A distance of 0.002 m separates two objects of equal mass. If the gravitational force between them is
Alika [10]

Answer: 24.97 kg

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F = G*(M1*M2)/R^2

Where G is the gravitational constant:

G = 6.67*10^-11 m^3/(kg*s^2)

In this case, we know that

R = 0.002m

F = 0.0104 N

and that M1 = M2 = M

And we want to find the value of M, then we can replace those values in the equation to get

0.0104 N = (6.67*10^-11 m^3/(kg*s^2))*(M*M)/(0.002m)^2

(0.0104 N)*(0.002m)^2/(6.67*10^-11 m^3/(kg*s^2)) = M^2

623.69 kg^2 = M^2

√(623.69 kg^2) = M = 24.97 kg

This means that the mass of each object is 24.97 kg

6 0
3 years ago
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