A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched
<u>Explanation:</u>
Work, W = 2 J
Initial distance, = 30 cm
Final distance, = 42 cm
Force, F = 30 N
Stretched length, x = ?
We know,
W = 1/2 kΔx²
Δx = 42-30 cm = 12 cm = 0.12 m
2 J = 1/2 k X (0.12)²
k = 277.77 N/m
According to Hooke's law,
F = kx
30 N = 277.77 X x
x = 0.108 m
x = 10.8 cm
A distance of 10.8 cm beyond its natural length will a force of 30 N keep this spring stretched.
Answer:
The answer is below
Explanation:
Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:
V = kT, where V = volume and T = temperature, k = constant. Therefore:
V / T = k
Given that:
The new volume is 3.41 m³. That is it expands by 0.41 m³
(a)
The energy of a photon is given by:
where
is the Planck constant
is the speed of light
is the wavelength
For the microwave photon,
So the energy is
And converting into electronvolts,
(b)
For the energy of the photon, we can use the same formula:
For the visible light photon,
So the energy is
And converting into electronvolts,
(c)
For the energy of the photon, we can use the same formula:
For the x-ray photon,
So the energy is
And converting into electronvolts,