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andriy [413]
3 years ago
7

Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with

the club?
Physics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds

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A 57-kg woman holds a 6-kg package as she stands within an elevator which briefly accelerates upward at a rate of 0.15g. Determi
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Answer:

R = 710.7N

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Explanation:

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3 years ago
1)the car's engine power is 44000W. Explain this number in a physical sense
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Answer:

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2) P = 20 W

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V^{2} = U^{2} - 2gh

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