Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with

Question

4 years ago

7

the club?

1 answer:

Mekhanik [1.2K] · Answer 1 · 2021-12-21T16:57:40+03:00

Answer: 0.013 seconds

Explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds