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BartSMP [9]
3 years ago
13

How much work is done when 0.0042 C is moved through a potential difference of 12.0 V? Use W = qV A. 0.050 J B. 0.00035 J C. 290

0 J D. 12 J
Physics
1 answer:
Masja [62]3 years ago
4 0

Answer:

Work done by charge (W) = 0.050 (Approx)

Explanation:

Given:

Charge (q) = 0.0042 C

Potential difference(V) = 12.0 V

Find:

Work done by charge

Computation:

Work done(W) = qV

Work done by charge (W) = (0.0042)(12)

Work done by charge (W) = 0.0504

Work done by charge (W) = 0.050 (Approx)

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Answer:

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Explanation:

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Let's call the velocity that the car maintains for 10 seconds v_f_1, and the final velocity v_f_2.

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Answer:

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Explanation:

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Given that,

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