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Ulleksa [173]
3 years ago
14

What elements are most common in minerals?

Physics
2 answers:
Leokris [45]3 years ago
4 0
<span>These elements are what make up minerals. The two most common elements are Oxygen (O) at 47% and Silicon (Si) at 28%. Other common elements are Aluminium (Al) at 8%, Iron (Fe) at 5%, Calcium (Ca) at 3.5%, Sodium (Na) at 3%, Potassium (K) at 2.5% and Magnesium (Mg) at just 2%.
 The information I have provided to you is from google </span>
sasho [114]3 years ago
3 0
OXYGEN & SILICON are most common in minerals......
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Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe
Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * 10^{6} m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × 10^{-19} C

mass of electron  = 9.1 × 10^{-31} kg

Force in an electric field = q*E

potential energy is stored in the form of work done

potential energy = work done = Force * displacement

                                                   = q * (E * d)  

                                                   = q * (V) = 1.6 × 10^{-19} * 100

stored potential energy = kinetic energy in electric field

kinetic energy = 1/2 * m * v^{2}

                        = 1/2 *  9.1 × 10^{-31} *  v^{2}

equation both the equations

1/2 *  9.1 × 10^{-31} *  v^{2} = 1.6 × 10^{-17}

v^{2} = 0.352 * 10^{14} m/s

v^{2} = 35.2 * 10^{12}

    = 5.93 * 10^{6} m/s

To learn more about  kinetic energy in electric field  here

brainly.com/question/8666051

#SPJ4

3 0
1 year ago
In the z-scheme ____ is the initial electron donor and ____ is the final electron acceptor.
Alenkinab [10]

In the z-scheme, water is the initial electron donor and NADP+ is the final electron acceptor.

<u>Explanation: </u>

It is a process of photosynthesis. It occurs in photosynthetic chemical reaction. The z scheme is basically a term for representing the oxidation and reduction reaction occurring in plants during photosynthesis.

The water present in the chlorophyll pigment donates electrons and become the initial electron donor. Those electrons get transferred to NADP+ and forms NADPH. Thus, water acts as electron donor initially and so the final electron is NADP+.

6 0
3 years ago
HELP ME please
allochka39001 [22]

Answer:

Ruko zara kuch Time dedo na please

3 0
2 years ago
Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ

Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference

For the separation of the lines we use trigonometry

        tan θ = sin θ / cos θ = y / x

In interference experiments the angle is very small

          tan θ = sin θ = y / x

         d y / x = m λ

a) and b) We apply the equation to the first laser

          λ = d / 20

          d y / x = m d / 20

          y = m x / 20

          y = 1 4.80 / 20

          y = 0.24 m

The second laser

        λ = d / 15

          d y / x = m d / 15

          y = m x / 15

          y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

They ask us for the second maximum m = 2

            y₂ = 2 4.8 / 20

            y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

         y₃ = (m + ½) x / 15

         m = 3

         y₃ = (3 + ½) 4.8 / 15

         y₃ = 1.12 m

        Δy = 1.12 - 0.48

        Δy = 0.64 m

4 0
2 years ago
А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]​
azamat

Answer:

15.3 m/s

Explanation:

Radius of orbit= 6400+6300 = 12700 km

Circumference of orbit= 2*(22/7)*12700 =79796.45*10^3 m

Now,

       Speed= Distance / Time

                  = 79796.45*10^3/(24*60*3600)

                  = 15.3 m/s

4 0
2 years ago
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