<span>h ( t) = h(1 sec) = -16t^2 + 541
so h (2 sec) = -16*(2)^2 + 541 = -64 + 541 = <span>477 ft
Therefore, </span></span>the height of the rock after 2 seconds is 477 feet.
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The correct answer as the first one above !
Answer:
v = 87.57 m/s
Explanation:
Given,
The initial velocity of the car, u = 0
The final velocity of the car, v = 60 mi/hr
The time period of car, t = 8 s
= 0.00222 hr
The acceleration of the car is given by the formula,
a = (v -u) / t
= 60 / 0.00222
= 27027 mi/hr²
If the car has initial velocity, u = 50 mi/hr
The time period of the car, t = 5.0 s
= 0.00139 hr
Using first equations of motion
<em> v = u + at</em>
= 50 + (0.00139 x 27027)
= 87.57 mi/hr
Hence, the final velocity of the car, v = 87.57 mi/hr
Answer:
Pressure difference between Top and Bottom of the cylinder is given as

Explanation:
As we know that the force due to pressure is balanced by the weight of the cylinder
So we will have

so we have

so we have

so we have

Answer:
Acceleration due to gravity will be
.
Explanation:
We can use the gravitational force equation:

The F is equal to the weight of the astronaut, so we will have:


- M(e) is the mass of the earth

- R is the radius of the earth

- G is the gravitational constant

But the distance between the astronaut and the center of the earth is 2R, then we have:
Therefore the acceleration due to gravity will be
.
I hope it helps you!