Question

Assuming the diameters of the nucleus and atom are 10A

Answer 1

Answer:

2.95 $\times 10^{-9}$ is the fraction of the nucleus is present in atom.

Explanation:

Given:

The diameter of the nucleus - 10A

The diameter of atom - 1.5 A

From this, we can find the radius of nucleus and atom i.e.

For nucleus $=\frac{10}{2}$

For atom $= \frac{1.5}{2}$

Now, the fraction of nucleus $= \frac{volume of nucleus}{volume of atom}$

                                               = $\frac{4}{3}\pi (\frac{10}{2})\frac{3.14}{2}\pi (\frac{10}{2})^3$

  or,                                         = $(\frac{10}{1.5})^3$

                                               = 2.95 $\times 10^{-9}$

Therefore, 2.95 $\times 10^{-9}$ is the fraction of nucleus in the atom.