If the desk doesn't move, then it's not accelerating.
If it's not accelerating, then the net force on it is zero.
If the net force on it is zero, then any forces on it are balanced.
If there are only two forces on it and they're balanced, then they have equal strengths, and they point in opposite directions.
So the friction on the desk must be equal to your<em> 245N</em> .
<span>7.7 m/s
First, determine the acceleration you subject the sled to. You have a mass of 15 kg being subjected to a force of 180 N, so
180 N / 15 kg = 180 (kg m)/s^2 / 15 kg = 12 m/s^2
Now determine how long you pushed it. For constant acceleration the equation is
d = 0.5 A T^2
Substitute the known values getting,
2.5 m = 0.5 12 m/s^2 T^2
2.5 m = 6 m/s^2 T^2
Solve for T
2.5 m = 6 m/s^2 T^2
0.41667 s^2 = T^2
0.645497224 s = T
Now to get the velocity, multiply the time by the acceleration, giving
0.645497224 s * 12 m/s^2 = 7.745966692 m/s
After rounding to 2 significant figures, you get 7.7 m/s</span>
Answer:
15
Explanation:
mass, M = 5Kg
horizontal force, F_h = 40N
acceleration, a =5 m/s^2
frictional force, F_f =?
net force = ma
net force = F_h - F_f = 40N - F_f
40 - F_f = 5 x 5
- F_f = 25 - 40
multiply both side by -1
F_f = 40 - 25 = 15
the frictional force is 15N
Given:
initial angular speed,
= 21.5 rad/s
final angular speed,
= 28.0 rad/s
time, t = 3.50 s
Solution:
Angular acceleration can be defined as the time rate of change of angular velocity and is given by:
![\alpha = \frac{\omega_{f} - \omega _{i}}{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B%5Comega_%7Bf%7D%20-%20%5Comega%20_%7Bi%7D%7D%7Bt%7D)
Now, putting the given values in the above formula:
![\alpha = \frac{28.0 - 21.5}{3.50}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B28.0%20-%2021.5%7D%7B3.50%7D)
![\alpha = 1.86 m/s^{2}](https://tex.z-dn.net/?f=%5Calpha%20%3D%201.86%20m%2Fs%5E%7B2%7D)
Therefore, angular acceleration is:
![\alpha = 1.86 m/s^{2}](https://tex.z-dn.net/?f=%5Calpha%20%3D%201.86%20m%2Fs%5E%7B2%7D)