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Artyom0805 [142]
3 years ago
9

A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog on it's path 50m

ahead. If the total force applied on the breaking system on the car by the driver is 2000N what would most probably happen
Physics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

Driver hits the dog

Explanation:

From kinematics equation

v_f^{2}=v_i^{2}+2as and making a the subject

a=\frac {v_f^{2}-v_i^{2}}{2s}=\frac {0-20^{2}}{2*50}=-4m/s^{2}

F=ma=800*-4=-3200  N

The driver is required to apply a force of 3200 N to effectively not hit the dog. However, when the driver applies 2000 N, this is less the required force by 1200 N hence the driver hits the dog.

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Answer:

7.6 s

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Substituting 8.8 m/s for u, 138 m for s and 2.45 m/s2 for a then

v=\sqrt{8.8^{2}+2*2.45*138}\\v=27.45 m/s

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Substituting 27.45 m/s for v, 8.8 m/s for u and 2.45 m/s for a then

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