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Artyom0805 [142]
3 years ago
9

A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog on it's path 50m

ahead. If the total force applied on the breaking system on the car by the driver is 2000N what would most probably happen
Physics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

Driver hits the dog

Explanation:

From kinematics equation

v_f^{2}=v_i^{2}+2as and making a the subject

a=\frac {v_f^{2}-v_i^{2}}{2s}=\frac {0-20^{2}}{2*50}=-4m/s^{2}

F=ma=800*-4=-3200  N

The driver is required to apply a force of 3200 N to effectively not hit the dog. However, when the driver applies 2000 N, this is less the required force by 1200 N hence the driver hits the dog.

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Answer:

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Explanation:

given:

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γ∞=1.23 kg/m^3

solution:

since outside pressure is atm pressure vaccum can be defined by (P_1-P_2)

V_1=√2(P_1-P_2)/γ∞[\frac{A_t}{A_1}^2-1]

(P_1-P_2)=1913.31 N/m^2

6 0
3 years ago
What is the meaning of technology
slamgirl [31]
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5 0
3 years ago
Which of these instruments can be used to peedict a thunderstorm?
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8 0
3 years ago
A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force
Ghella [55]

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

F_c = \frac{mv^2}{r}\\\\

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v is the linear velocity of the object

F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s

Therefore, the linear velocity of the object is 8.71 m/s.

4 0
3 years ago
A scientific hypothesis can be disproved with a.one reproducible experiment. b.disapproval of other scientists. c.many tests by
joja [24]

Answer:

option A

Explanation:

The correct answer is option A

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hence, a scientific hypothesis can be disproved with one reproducible experiment.

6 0
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