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Ivenika [448]
3 years ago
8

3. Hexane (C6H-2) is combusted in oxygen

Chemistry
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

                   a)  9.5 moles of Oxygen

                    b)  1.029 × 10²⁵ Molecules

Explanation:

                    The balance chemical equation for said reaction is as follow:

                               2 C₆H₁₄ + 19 O₂   →  12 CO₂ + 14 H₂O

A)

According to equation,

              2 moles of C₆H₁₄ are reacted with  =  19 moles of O₂

So,

                   1 moles of C₆H₁₄ will react with  =  X moles of O₂

Solving for X,

                      X  =  19 moles × 1 mole / 2 moles

                       X  =  9.5 moles of Oxygen

B)

For this part first calculate moles of hexane as;

                             Moles  =  Mass / M.Mass

                             Moles  =  245.5 g / 86.18 g/mol

                             Moles  =  2.84 mole of Hexane

Secondly, find the number of moles of CO₂ as,

According to equation,

              2 moles of C₆H₁₄ produced  =  12 moles of CO₂

So,

                   2.84 moles of C₆H₁₄ will produce  =  X moles of CO₂

Solving for X,

                      X  =  12 moles × 2.84 mole / 2 moles

                       X  =  17.09 moles of CO₂

Lastly, calculate the number of molecules of CO₂ as,

Number of Molecules  =  Moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  17.09 moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  1.029 × 10²⁵ Molecules

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lubasha [3.4K]

Answer:

the amounts and compositions of the overflow V1 and underflow L1 leaving the stage are 75kg and 125kg respectively.

Explanation:

Let state the given parameters;

Let A= solvent (hexane)

B= solid(inert soiid)

C= solvent(oil)

F_{solution} = mass of solvent + mass of oil (i.e A+C)

<u>Feed Phase:</u>

Total feed (i.e slurry of flakes soybeans)= 100kg

B= mass of solid =75 kg

F= mass of solvent + mass of oil (i.e A+C)

 = 25kg

Mass ratio of oil to solution Y_{F} =\frac{Mass C}{Mass (A+C)}

mass of oil (C) =25 × 0.1 wt = 2.5kg

mass of hexane  in feed = 25 ×  0.9 =22.5kg + 2.5 =25kg

therefore  Y_{F} = \frac{2.5}{25}

= 0.1

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<u>Solvent Phase:</u>

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A= Mass of hexane = 100kg

mass of solutions = A+C = 0+100kg

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<u>Underflow:</u>

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L₁ = E₁ + B

the value of N for the outlet and underflow is 1.5 kg

i.e N₁ = \frac{mass B}{mass(A+C)}

solution in underflow E₁ = Mass (A+C)

<u>Overflow:</u>

Overflow = V₁ = (unknown) ???

solution in overflow V₁ = Mass (A+C)

This is because, B = 0 in overflow

Solid Balance: (since the solid is inert, then is said to be same in feed & underflow).

solid in feed = solid in underflow = 75

75=  E₁ × N₁

75 =  E₁ × 1.5

E₁ = 50kg

Underflow L₁ = E₁ × B

= 50 + 75

=125kg

The Overall Balance: Feed + Solvent = underflow + overflow

100 + 100 = 125 + V₁

V₁ = 75kg

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Explanation:

The problem is very simple. It involves conversion from mass to number of moles of NaCl

What is mole?

 A mole is a unit of measuring chemical substances. It is the amount that contains the avogadro's number of particles.

How is it related and can be converted from mass;

 

Number of moles of a substance = \frac{mass}{molar mass}

Since we know the mass, we can find the molar mass and put into this equation;

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Number of moles of NaCl = \frac{5}{58.5}  = 0.086mole

learn more:

Number of moles brainly.com/question/1841136

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