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Serga [27]
3 years ago
5

Can you give answers to some questions that you know?(Mostly page 2)

Physics
1 answer:
Fudgin [204]3 years ago
4 0

the moon is illminated

tracing paper is not transparent

hope i helped

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A cylinder-piston system contains an ideal gas at a pressure of 1.5 105 pa.
Sedbober [7]

The change in the internal energy of the ideal gas is determined as -28 J.

<h3>Work done on the gas</h3>

The work done on the ideal gas is calculated as follows;

w = -PΔV

w = -1.5 x 10⁵(0.0006 - 0.0002)

w = -60 J

<h3>Change in the internal energy of the gas</h3>

ΔU = w + q

ΔU = -60J + 32 J

ΔU = -28 J

Thus, the change in the internal energy of the ideal gas is determined as -28 J.

Learn more about internal energy here: brainly.com/question/23876012

#SPJ1

5 0
2 years ago
I need these for test corrections that are due tomorrow please :)
Ivahew [28]
That would be position Y, as the northern hemisphere is tilted away from the sun.
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3 years ago
The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation f
Hoochie [10]
<span>Answer: F(x) = ax^2 - bx or F(x) = ax² - bx F(x) = 30x² - 6x â«F(x)dx = â«(30x² - 6x)dx as this is evaluated from zero to x W = 10xÂł - 3x² <===ANS W = 10(0.42Âł) - 3(0.42²) - [10(0Âł) - 3(0²)] W = 0.212 J <===ANS W = 10(0.72Âł) - 3(0.72²) - [10(0.42Âł) - 3(0.42²)] W = 1.966 J <===ANS</span>
5 0
3 years ago
A wave is a:
liraira [26]

Answer:

wave

Explanation:

5 0
3 years ago
A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
andrey2020 [161]

Answer:

The magnitude of force is 1593.4N

Explanation:

The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as

fcostheta + Nsintheta = mv^2/r

Where F = force of friction

Theta = angle of banking

N = normal force

m = mass of car

v = velocity of car

r = radius of curve

The car has no motion in the vertical direction so the sum of forces = 0

The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.

Taking the upward direction to be positive,rewrite the equation above to get:

Ncos thetha = mg - fsintheta =0

Ncistheta = mg + fain theta

N = mg/cos theta + sintheta/ costheta

fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r

Substituting gives:

f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)

Substituting given values into the above equation

f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan

f = 1593.4N25

4 0
3 years ago
Read 2 more answers
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