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bonufazy [111]
2 years ago
5

The method used in this experiment is sometimes called the vapor density method. The ideal gas equation can be rearranged to sol

ve for the density of a vapor . Which type or types of measurement is not needed to calculate the density of a gas?
Chemistry
1 answer:
TiliK225 [7]2 years ago
6 0
The correct answer for the question that is being presented above is this one: "B) Temperature."
Here are the following choices:

A) all of these measurements are needed

B) Temperature

C) Molar Mass

D) Pressure

E) Mass

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Vanyuwa [196]

Answer:

yo try and search it on Google

4 0
3 years ago
Solution A has twice as much solute as solution B is it possible for the solutions to have the same concentration
pishuonlain [190]
Yes. As long as the ratio of solute and solvent is same for both solution, the solution has the same concentration. for example, solution A has 2 ml of water, and 1 ml of sucrose. Solution B has 4ml of water and 2ml of sucrose. Both has a ratio of water to sucrose by 2 : 1. they have the same concentration of 50% sucrose. 
5 0
3 years ago
Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the perce
kondor19780726 [428]

Answer:

29.41% of Calcium and 47.04% of Oxygen

Explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen

5 0
2 years ago
Si2Br6 compound name
Anna71 [15]

Answer:

disilicon hexabromide

Explanation:

6 0
2 years ago
For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.
Anton [14]

Answer:-  2.4 mol NO_2 .

Solution:- It asks to calculate the moles of NO_2 formed when 1.2 moles of N_2O_5 are reacted.

There is 2:4 mol ratio between N_2O_5 and NO_2 . So, the moles of reactant are multiplied by the mol ratio to get the moles of NO_2 . The calculations are shown below:

1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})

= 2.4 mol NO_2

So, 2.4 moles of NO_2 are formed when 1.2 moles of  N_2O_5 were reacted.

7 0
3 years ago
Read 2 more answers
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