Answer & explanation:
To balance a chemical equation, we must make sure that there are equal amounts of each element in the equation on either side.
To balance an equation step-by-step we first start by counting the amount of each element on each side. If they aren't equal, we must make them amounts equal on either side.
After you make sure all the elements are balanced, the net charge on both sides must also be equal.
Answer:
+1, lose, 1, 4s, 4s and 3d
Explanation:
<em>An element with the valence electron configuration 4s¹ would form a monatomic ion with a charge of </em><em>+1</em><em>. In order to form this ion, the element will </em><em>lose</em><em> </em><em>1 </em><em>electron from the </em><em>4s </em><em>subshell.</em>
The corresponding oxidation reaction is:
K ⇒ K¹⁺ + 1 e⁻
[Ar] 4s¹ ⇒ [Ar]
<em>If an element with the valence configuration 4s² 3d⁶ loses 3 electrons, these electrons would be removed from the </em><em>4s and 3d</em><em> subshell(s).</em>
The corresponding oxidation reaction is:
Fe ⇒ Fe³⁺ + 3 e⁻
[Ar] 4s² 3d⁶ ⇒ [Ar] 4s⁰ 3d⁵
Answer:
NH₄Cl (aq) + NaOH (aq) -> NaCl (aq) + H₂O (l) + NH₃ (g)
(NH₄)₂CO₃ (aq) + 2KOH (aq) -> K₂CO₃ (aq) + 2H₂O (l) + 2NH₃(g)
NH₄NO₃ (aq) + LiOH (aq) -> LiNO₃ (aq) + H₂O (l) + NH₃ (g)
Explanation:
The gas liberated when an alkali reacts with an ammonium salt is NH₃ (ammonia), not CO₂.
<span>The answer would be: The two substances are not the same because the property that is independent of the amount of the sample is different.<span>
The two substances has different solubility which is </span></span>36 g/mL and <span>180 g/mL. The same kind of molecule should have same density and solubility, regardless the mass of the sample. In this case, the substances are not same since it has different solubility.</span>
Answer:
The first thing we have to do is change and state all the units so that we can use our ideal gas law equation (
).
650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.
P = 86kPa
T = 15°C + 273K = 288K
R (Gas constant) = 8.31 kj/mol
Molar mass of Ammonia (
) = (1 x 3) + (14) = 17g/mol
n (moles) = 
3.34 mol
V = ?
Rearrange the equation to solve for Volume:
Substitute the values inside:
V = 
<u>Therefore 93 L of volume is occupied by the ammonia gas.</u>
<u></u>
