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Bumek [7]
3 years ago
14

Kepler’s third law can be used to derive the relation between the orbital period, P (measured in days), and the semimajor axis,

A (measured in AU), of an orbiting body. The relation is given by the equation P2 = kA3, where k is a constant value for all bodies orbiting that star. The semimajor axis of Mars is 1.52 AU, and its orbital period is about 687 days. What is the value of the constant k?
Physics
2 answers:
NikAS [45]3 years ago
8 0
Kepler's 3rd law is given as
P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant

Given:
P = 687 days
A = 1.52 AU

Therefore
k = P²/A³ = 687²/1.52³ = 1.3439 x 10⁵ days²/AU³

Answer:  1.3439 x 10⁵ (days²/AU³)

miss Akunina [59]3 years ago
8 0

Answer:

The answer is 1.34 × 10⁵

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6 0
3 years ago
The sensor in the torso of a crash test dummy records the magnitude and direction of the net force acting on the dummy.If the du
Sunny_sXe [5.5K]

Here in crash test the two forces are acting on the dummy in two different directions

As we know that force is a vector quantity so we need to use vector addition laws in order to find the resultant force on it.

So here two forces are given in perpendicular direction with each other so as per vector addition law we need to use Pythagoras theorem to find the resultant of two vectors

so we can say

F_{net} = \sqrt{F_1^2 + F_2^2}

here given that

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F_2 = 4500.0 N

now we will plug in all data in the above equation

F_{net} = \sqrt{4500^2 + 130^}

F_{net} = 4501.9 N

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4 0
3 years ago
Read 2 more answers
If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc
Allisa [31]

Answer:

the net force applied to the car is zero.

Explanation:

According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):

a=\frac{F}{m}

where m is the object's mass.

In this problem, the car is moving with constant velocity: this means that the acceleration is zero, a = 0. Therefore, according to the previous equation, the net force must also be zero: F = 0. So, the correct answer is

the net force applied to the car is zero.

3 0
3 years ago
On the way to school, the bus speeds up from 20 m/s to 36 m/s in 4 seconds. What distance
Tresset [83]
Answer B. 112 m



Step-by-Step Explanation

initial velocity u = 20 m /s
final velocity v = 36 m /s
time taken t = 4 s
acceleration = (v - U) / t
= (36 - 20) / 4
a=4m/s2
from the formula
7-u2=2as , sis distance covered
putting the values
362-202=2×4×s
1296 - 400 = 8 x S
S= 112 m
4 0
2 years ago
A six pack of your favorite beverage (12 fl. oz. cans, assumed to have the same characteristics as water) is placed in a cooler
nasty-shy [4]

Answer:

Q = 169 BTU

Explanation:

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now we have six pack of such volume

so total volume is given as

V = 6\times 0.355 Ltr

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so its mass is given as

m = 2.13 kg

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\Delta T = 20^oC

now the heat given to the liquid is given as

Q = ms\Delta T

Q = 2.13(4186)(20)

Q = 1.78 \times 10^5 J

Q = 169 BTU

4 0
3 years ago
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