The potential energy of the skateboarder at the top of the ramp is
489.1 J.
<h3>Is kinetic energy always equal to potential energy?</h3>
The amount of kinetic energy change and the amount of potential energy change are equal in all physical processes that take place in closed systems. When the kinetic energy rises, the potential energy falls, and vice versa.
Potential energy is the stored energy in any object or system as a result of its position or component arrangement. However, external factors like air or height have no effect on it. The energy of a moving object or system is referred to as kinetic energy.
Potential energy = kinetic energy
Potential energy = 1/2mv²
Potential energy = 1/2 × 67×7.3
Potential energy = 489.1 J.
To know more about kinetic energy visit:
brainly.com/question/26472013
#SPJ1
The first law of thermodynamics is expresses by
D. ΔU=Q-W
which means change in internal energy of system = Heat added to system minus work done by the system
All are expressed in Joules.
This law is based on principle of conservation of energy.
Answer:
The density of the mixture is 0.55kg/m^3
Explanation:
P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole
PV = nRT
V = nRT/P = 1×8.314×273/100 = 22.70m^3
Mass of N2 = 0.4×28 = 11.2kg
Mass of H2 = 0.6×2 = 1.2kg
Mass of mixture = 11.2 + 1.2 = 12.4kg
Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3
Answer:
A) 1.4167 × 10^(-11) F
B) r_a = 0.031 m
C) E = 3.181 × 10⁴ N/C
Explanation:
We are given;
Charge;Q = 3.40 nC = 3.4 × 10^(-9) C
Potential difference;V = 240 V
Inner radius of outer sphere;r_b = 4.1 cm = 0.041 m
A) The formula for capacitance is given by;
C = Q/V
C = (3.4 × 10^(-9))/240
C = 1.4167 × 10^(-11) F
B) To find the radius of the inner sphere,we will make use of the formula for capacitance of spherical coordinates.
C = (4πε_o)/(1/r_a - 1/r_b)
Rearranging, we have;
(1/r_a - 1/r_b) = (4πε_o)/C
ε_o is a constant with a value of 8.85 × 10^(−12) C²/N.m
Plugging in the relevant values, we have;
(1/r_a - 1/0.041) = (4π × 8.85 × 10^(−12) )/(1.4167 × 10^(-11))
(1/r_a) - 24.3902 = 7.8501
1/r_a = 7.8501 + 24.3902
1/r_a = 32.2403
r_a = 1/32.2403
r_a = 0.031 m
C) Formula for Electric field just outside the surface of the inner sphere is given by;
E = kQ/r_a²
Where k is a constant value of 8.99 × 10^(9) Nm²/C²
Thus;
E = (8.99 × 10^(9) × 3.4 × 10^(-9))/0.031²
E = 3.181 × 10⁴ N/C
Answer:
1.2
Explanation:
2.0 mol O₂ × (3 mol CO₂ / 5 mol O₂) = 1.2 mol CO₂
