Im pretty sure the answer if elasticity
(a) By definition of average acceleration,
<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (0 - 38 m/s) / (5.0 s)
<em>a</em> = -7.6 m/s²
(b) Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>x</em> is the change in position. So
0² - (38 m/s)² = 2 (-7.6 m/s²) ∆<em>x</em>
∆<em>x</em> = 95 m
A. The restoring force is tripled
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Answer:
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.
Explanation:
Given that,
The mass of a ball, m = 2 kg
Kinetic energy of the ball, K = 25 J
We need to find the speed of the ball. The formula for the kinetic energy is given by :
So,
A 2-kg ball is thrown at a speed of 5 m/s, exhibits 25 J of kinetic energy.
