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ra1l [238]
2 years ago
5

The slope of a speed-time graph indicates. A. direction. . B. acceleration. . C. velocity. . D. speed.

Physics
2 answers:
liberstina [14]2 years ago
8 0
The y-axis of the speed-time graph is the speed while the x-axis is the time of travel. In this case, the slope is equal to the change in y over change in x. Change in y is velocity difference while change in x is time difference. Since v<span>elocity difference/ t</span><span>ime difference is the slope, the answer is acceleration. </span>
Blizzard [7]2 years ago
7 0
B. Acceleration Velocity and speed are the same thing btw
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DIA [1.3K]

Responder:

20πrads ^ -1; 24πrads ^ -1; 0,1 seg; 10 Hz

Explicación:

Dado lo siguiente:

Radio (r) del círculo = 120 cm

600 revoluciones por minuto en radianes por segundo

(600 / min) * (2π rad / 1 rev) * (1min / 60seg)

(1200πrad / 60sec) = 20π rad ^ -1

Velocidad angular (w) = 20πrads ^ -1

Velocidad lineal = radio (r) * velocidad angular (w)

Velocidad lineal = (120/100) * 20πrad

Velocidad lineal = 1.2 * 20πrads ^ -1 = 24πrads ^ -1

C.) Período (T):

T = 2π / w = 2π / 20π = 0.1 seg

D.) Frecuencia (f):

f = 1 / T = 1 / 0.1

1 / 0,1 = 10 Hz

5 0
3 years ago
A book sitting on a table is moved horizontally. Describe the
Akimi4 [234]

Frictional force and Applied force has same “magnitude” and “opposite” direction.  

Option: B  

<u>Explanation</u>:  

When a book is moved horizontally by applying “force” on the book, the frictional force is opposed to the book by the table. Here, this “frictional force” is opposing the book has the same force what we applied on the book but this frictional force and the applied force are opposite in direction. Always the “frictional force” is opposite to the “applied force” which stops the object to move. For example, if a force applied leftward to the object the frictional force is acted on the right side of the object.

When two objects are in contact they experience a "frictional force". This "frictional force" acts opposite to the force applied on to move the object.

Formula for "frictional force" is \mu\times N

Where, \mu is coefficient of friction and N is normal force.

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Explanation:

<u>Kinetic Energy </u>

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\displaystyle K=\frac{mv^2}{2}

Both runners are moving in a horizontal path, thus they have kinetic energy, given by the above equation. If they could jump below ground level, then they will also have potential energy

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Answer:

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