Question

A small, 150 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 5.00 kg cart at rest. After the collision, the small cart recoils at 0.890 m/s. What is the speed of the large cart after the collision?

Answer 1

Answer:

Mass of larger cart will be 0.0213 m /sec

Explanation:

We have given mass of small cart $m_1=150gram=0.150kg$

Initial velocity of small cart $v_{1i}=1.6m/sec$

Mass of larger block $m_2=5kg$

Initial velocity of larger cart $v_{2i}=0m/sec$

After the collision velocity of smaller cart $v_{1f}=-0.890m/sec$

Now according conservation of momentum

$m_1v_{1i}+m_2v_{2i}=m_1v{1f}+m_2v_{2f}$

$0.150\times 1.6+5\times 0=0.150\times -0.890+5\times v_{2f}$

$5\times v_{2f}=0.1065$

$v_{2f}=0.0213m/sec$