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Anna71 [15]
4 years ago
8

Trevor lifts a 10kg box to the top of a cliff which is 20m high, in half an hour, then drops the box over the cliff. How much po

wer did he use to lift the box?
Physics
1 answer:
Reil [10]4 years ago
6 0

Answer:

P=1.11Watts

Explanation:

Mass if box: m=10kg

Height: h=20m

g=10m/s²

Duration of action: t=30min=1800s

Work to lift the box:

W=m×g×h=10×10×20=2000J

Power: P=W/t=2000/1800=1.11Watts

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Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,
Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0
3 years ago
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its e
kirill115 [55]

Answer:

378 KWh

Explanation:

We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:

10³ W = 1 KW

Therefore,

1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W

1.2×10³ W = 1.2 KW

Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:

60 mins = 1 h

Therefore,

6.3×10² mins = 6.3×10² mins × 1 h / 60 mins

6.3×10² mins = 10.5 h

Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:

Power (P) = 1.2 KW

Time (t) for 1 month (30 days) = 10.5 h × 30

= 315 h

Energy (E) =?

E = Pt

E = 1.2 × 315

E = 378 KWh

Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.

8 0
3 years ago
Write a letter to a Friend congratulating her / him for her excellent result in annual examination. class 5 the​
gulaghasi [49]

Answer:

ok will do that

Explanation:

7 0
3 years ago
Add a small ball to a graduated cylinder containing 10 milliliters of water.
malfutka [58]
The volume of water will increase . If yu subtract the original volume from the new volume of water you will get the volume of the small ball.
8 0
3 years ago
I need help please :)
Masja [62]

Answer:

20

Explanation:

AB, AC, AD, AE, BC, BD, BE, ....

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