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Levart [38]
3 years ago
15

Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it

holds 375 g of coffee when filled to a depth of 7.50 cm
Physics
1 answer:
N76 [4]3 years ago
6 0

Answer:

0.0399 m

Explanation:

We are given that

Mass of coffee=375g=\frac{375}{1000}=0.375 kg

1kg=1000g

Depth=h=7.5 cm=7.5\times 10^{-2} m

1 cm=10^{-2} m

Density of coffee=\rho=1000kg/m^3

We have to find the inside radius  of coffee mug.

We know that

\rho=\frac{m}{V}

Substitute the values

1000=\frac{0.375}{\pi r^2h}

r^2=\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}

By using \pi=3.14

r=\sqrt{\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}}

r=0.0399 m

Hence, the inside radius=0.0399 m

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