Question

Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it holds 375 g of coffee when filled to a depth of 7.50 cm

Answer 1

Answer:

0.0399 m

Explanation:

We are given that

Mass of coffee=375g=$\frac{375}{1000}=0.375 kg$

1kg=1000g

Depth=h=7.5 cm=$7.5\times 10^{-2} m$

$1 cm=10^{-2} m$

Density of coffee=$\rho=1000kg/m^3$

We have to find the inside radius  of coffee mug.

We know that

$\rho=\frac{m}{V}$

Substitute the values

$1000=\frac{0.375}{\pi r^2h}$

$r^2=\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}$

By using $\pi=3.14$

$r=\sqrt{\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}}$

$r=0.0399 m$

Hence, the inside radius=0.0399 m