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Levart [38]
3 years ago
15

Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it

holds 375 g of coffee when filled to a depth of 7.50 cm
Physics
1 answer:
N76 [4]3 years ago
6 0

Answer:

0.0399 m

Explanation:

We are given that

Mass of coffee=375g=\frac{375}{1000}=0.375 kg

1kg=1000g

Depth=h=7.5 cm=7.5\times 10^{-2} m

1 cm=10^{-2} m

Density of coffee=\rho=1000kg/m^3

We have to find the inside radius  of coffee mug.

We know that

\rho=\frac{m}{V}

Substitute the values

1000=\frac{0.375}{\pi r^2h}

r^2=\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}

By using \pi=3.14

r=\sqrt{\frac{0.375}{1000\times 7.5\times 10^{-2}\times 3.14}}

r=0.0399 m

Hence, the inside radius=0.0399 m

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If Anya decides to make the star twice as massive, and not change the length of any crossbar or the location of any object, what
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4 0
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"State the process that divides one nucleus into two genetically identical nuclei"
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b) This points to a perfectly inelastic collision between the ball and the floor as they stick together after collision

c) Check Explanation.

Explanation:

Collision of bodies are analysed according to whether both momentum and kinetic energy of the system is conserved, that is, if these two quantities before collision are equal to their values after collision.

In all types of collisions, momentum is usually conserved, but kinetic energy is conserved only in an elastic collision.

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b. If the ball had not bounced at all, how would you describe the collision between the ball and the floor?

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c. What happened to the energy lost by the ball during thecollision?

The energy lost during the collision is converted to another form, most likely responsible for some deformation on the ball & a minute deformation on the floor, converted to some form of heat as a result of the collision or into sound energy, usually, it's a combination of all This!

Hope this Helps!!!

5 0
3 years ago
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