The spectrum of light emitted by helium atoms is different than that emitted by hydrogen atoms because

Physics

1 answer:

MaRussiya [10]3 years ago

4 0

<h3><u>Answer;</u></h3>

The different atoms have different quantized energy levels

<h3><u>Explanation;</u></h3>

The atoms of different elements have different energy levels because they have different nuclear charges and spins, and different numbers of electrons.
Each different kind of atom, like hydrogen or radon, has a distinct nuclear charge and number of electrons. This makes the potential energy function different for each atom, and therefore results in different energy levels.
In an emmission spectra, each bright band corresponds to a difference between energy levels within the atom.

You might be interested in

Which statement best describes a characteristic of gases?

salantis [7]

Assumes the shape and volume of its container
<span>particles can move past one another</span>

8 0

3 years ago

4.72 A full-wave bridge-rectifier circuit with a 1-k load operates from a 120-V (rms) 60-Hz household supply through a 12-to-1 s

melisa1 [442]

Answer:

a) 12.74 V

b) Two pairs of diode will work only half of the cycle

c) 8.11 V

d) 8.11 mA

Explanation:

The voltage after the transformer is relationated with the transformer relationshinp:

$V_o=Vrms*\frac{1}{12}\\V_o=10Vrms$

the peak voltage before the bridge rectifier is given by:

$V_{op}=Vo*\sqrt{2}\\V_{op}=14.14V$

The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:

$V_l=V_{op}-2(0.7)\\V_l=12.74V$

As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.

The averague voltage on a full wave rectifier is given by:

$V_{avg}=2*\frac{V_l}{\pi}\\V_{avg}=8.11V$