The stereo uses an energy of
in a time
, therefore the power of the stereo is given by
We also know that the power of an electrical device is related to its voltage, V, and its resistance, R, by the following equation
therefore, we can rearrange the equation to calculate the resistance of the stereo:
Answer:
The motion of a simple pendulum is very close to Simple Harmonic Motion (SHM). SHM results whenever a restoring force is proportional to the displacement, a relationship often known as Hooke's Law when applied to springs. Where F is the restoring force, k is the spring constant, and x is the displacement.
where θ is the angle the pendulum makes with the vertical. For small angles, sin(θ)∼θ, which would then lead to simple harmonic motion. For large angles, this approximation no longer holds, and the motion is not considered to be simple harmonic motion.
Answer:
10.8 N
Explanation:
The question requires the force between them, hence, we only need the magnitude of the force without considering what direction it's acting.
Parameters given:
Q1 = 15 * 10^(-6) C
Q2 = 10 * 10^(-6) C
The diagram explains better.
The electrostatic force BETWEEN Q1 and Q2 is:
F = (k * Q1 * Q2)/r²
Using Pythagoras theorem:
r² = 0.25² + 0.25² = 0.0625 + 0.0625
r² = 0.125
=> F = [9 * 10^9 * 15 * 10^(-6) * 10 * 10^(-6)]/0.125
F = 1.35/0.125
F = 10.8 N
Answer:
linear charge density = -9.495 × 
C/m
Explanation:
given data
revolutions per second = 1.80 × 
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 × 
× 
q = m × w² × r ............2
and w = 
w = 
w = 1.80 × × 
w = 11304000 rad/s
so here from equation 2
- 9 × × 
1.80 × = 1.672 × 
× 11304000² × 0.0120
linear charge density = -9.495 × C/m
