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3 years ago

The spectrum of light emitted by helium atoms is different than that emitted by hydrogen atoms because

Physics

1 answer:

MaRussiya [10]3 years ago

4 0

<h3><u>Answer;</u></h3>

The different atoms have different quantized energy levels

<h3><u>Explanation;</u></h3>

The atoms of different elements have different energy levels because they have different nuclear charges and spins, and different numbers of electrons.
Each different kind of atom, like hydrogen or radon, has a distinct nuclear charge and number of electrons. This makes the potential energy function different for each atom, and therefore results in different energy levels.
In an emmission spectra, each bright band corresponds to a difference between energy levels within the atom.

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A car is traveling at 96km/hr. what is the acceleration of a car traveling a distance of 100m and come to rest?

8090 [49]

Answer:

Explanation:

v² = u² + 2as

v = 0

u = 96 / 3.6 = 26.7 m/s

0² = 26.7² + 2a100

a = -3.5555555... ≈ -3.6 m/s²

the negative sign indicated the acceleration vector opposes the (assumed positive) initial velocity vector direction.

6 0

2 years ago

Consider a glider flying at 400 meters altitude, when suddenly all its static ports become blocked by volcanic ash. The pressure

Furkat [3]

Answer:

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

Explanation:

Pitot tube

$U = \sqrt{\frac{(p_t - p_s)2}{d} }$

U = velocity(m/s)

$p_t$ = stagnation pressure (pa)

$p_s$ = static pressure (pa)

d = fluid density(kg/m³)

$p_t = p_a_t_m + \frac{1}{2} dv^2$

v = true velocity

= 101325 + 1/2(1.225)(25)²

$p_t = 101,707.8125pa$

$p_s = 96,610pa$

d = 1.225kg/m³

$U = \sqrt{\frac{2(101,707.8125 - 96,610)}{1.225} } \\\\U = 91.23m/s$

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

5 0

3 years ago

How does self efficacy relate to sports performance?

vitfil [10]

Answer: Individuals with high self efficacy will participate readily and more frequently, will put more effort in and persist longer, enhancing performance in sport and exercise

6 0

2 years ago

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 44.1m/s^2 . The acce

ollegr [7]

The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>

7 0

3 years ago

The acceleration of automobiles is often given in terms of the time it takes to go from 0 mi/h to 60 mi/h. One of the fastest st

Rudiy27

Answer:

9.934 m/s²

Explanation:

Given:

Initial speed of the Bugatti Veyron Super Sport = 0 mi/h

Final speed of the Bugatti Veyron Super Sport = 60 mi/h

Now,

1 mi/h = 0.44704 m / s

thus,

60 mi/h = 0.44704 × 60 = 26.8224 m/s

Time = 2.70 m/s

Now,

The acceleration (a) is given as:

$a=\frac{\textup{Change in speed}}{\textup{Time}}$

thus,

$a=\frac{26.8224 - 0 }{2.70}$

a = 9.934 m/s²

6 0

2 years ago