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ZanzabumX [31]
4 years ago
5

A collection of coins contains 14 pennies, 16 dimes, and 7 quarters. What is the percentage of pennies in the collection?A colle

ction of coins contains 14 pennies, 16 dimes, and 7 quarters. What is the percentage of pennies in the collection?
Chemistry
2 answers:
marin [14]4 years ago
8 0

Answer:

=37.83783784

Explanation:

Find the total sum of all coins,

which is 37, take the number of pennies and the total of all coins put in parenthesis( 14/37) like so and than * times them by 100

you equation should look like this

(14/37)* 100= and than the answer shown above should be the one you received. I have checked this with multiple calculators, it should be accurate.  

Nesterboy [21]4 years ago
7 0

Answer : The percentage of pennies in the collection is 37.84 %.

Explanation :

To calculate the percentage of pennies in the collection, we use the equation:

\text{Percentage of pennies}=\frac{\text{Coins of pennies}}{\text{Total number of coins}}\times 100

Given:

Number of coins of pennies = 14

Number of coins of dimes = 16

Number of coins of quarters = 7

Now we have to calculate the total number of coins.

Total number of coins = 14 + 16 + 7 = 37

Now we have to calculate the percentage of pennies in the collection.

\text{Percentage of pennies}=\frac{14}{37}\times 100=37.84\%

Hence, the percentage of pennies in the collection is 37.84 %.

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Rank these acids according to their expected pKa values.
givi [52]

Answer:

According to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

Explanation:

The pKa values are the negative logarithm of dissociation constant. It represents the relative strengths of the acids. Stronger acids show smaller pKa values and weak acids present larger pKa value. The stronger the acid, the weaker it's the conjugate base. The larger the pKa of the conjugate base, the stronger the acid. The strength of an acid is inversely related to the strength of its conjugate.

Conjugate bases are the substance that has one less proton than the parent acid. The conjugate base of the acid presented in the problem are:

ClCH2COOH -> ClCH2COO-  + H+

ClCH2CH2COOH -> ClCH2CH2COO- + H+

CH3CH2COOH -> CH3CH2COO- + H+

Cl2CHCOOH -> Cl2CHCOO - + H+

Cl2CHCOOH. The negative charge presented on its conjugate base is by resonance and inductive effect. This is the strongest acid.

ClCH2COOH. A negative charge is stabilized by resonance and electron-withdrawing but only one atom is present. So this acid is less strong than the first one.

ClCH2CH2COOH. The negative charge is stabilized by resonance and electron-withdrawing atom but the effect is less compared to the two acids showed previously.

CH3CH2COOH. The negative charge is stabilized by resonance and destabilized due to CH3 group. This is the weakest acid among the problem.

Stronger acids have smaller pKa values and weak acids have larger pKa values. Due to the information present in this problem, Cl2CHCOOH is the strongest acid and the lowest pKa. CH3CH2COOH is the weakest acid, so the highest pKa value.

Finally, we can conclude that according to their expected pKa values, the order of those acids should be:

1- Cl2CHCOOH is the strongest acid and the lowest pKa.

2- ClCH2COOH is a strong acid, but no more than the first. Medium pKa value.

3- ClCH2CH2COOH is a strong acid, but no more than the two previous acids. High pKa value.

4- CH3CH2COOH  is the weakest acid, so the highest pKa value.

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3 years ago
Draw the Lewis structure for the polyatomic formate anion. Be sure to include all resonance structures that satisfy the octet ru
givi [52]

Answer:

Lewis structure of polyatomic formate anion.

Explanation:

To draw Lewis structure for any chemical species,

1)Count the total number of valence electrons present in it.

This can be obtained by adding valence electrons of each constituent atom.

2)Arrange those valence electrons in such a way that each atom should attain eight electrons around it to satisfy octet theory.

The structure of formate ion and its Lewis structure are shown below:

HCOO- is the formate ion.

It has total:

1+4+6+6+1 = 18 valence electrons.

Since, hydrogen has one, carbon has four and oxygen has six valence electrons and the charge of the anion is one.

Arrange this 18 electrons in such a way that each atom should get 8 electrons around it.

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vfiekz [6]

Explanation:

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Marat540 [252]
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Rzqust [24]

Answer:

FeSO₄ + 2NaOH  →  Fe(OH)₂  +  Na₂SO₄

Explanation:

The equation for the reaction is:

FeSO₄ + 2NaOH  →  Fe(OH)₂  +  Na₂SO₄  

Dissociation of each compound

FeSO₄ → Fe²⁺  +  SO₄⁻²

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Fe(OH)₂ →  Fe²⁺  +  2OH⁻

Na₂SO₄ → 2Na⁺  +  SO₄⁻²

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