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cupoosta [38]
3 years ago
14

a 100 gram sample of iron ore was found to contain 44g of iron. How many grams of iron are in a 450 gram sample of the ore?

Chemistry
1 answer:
Sphinxa [80]3 years ago
7 0

Answer:

There are 198 grams of iron in a 450-gram sample of the ore.

Explanation:

From the given information:

Given that:

100-gram sample of iron ore is found in 44g of iron.

Thus. the grams of iron that can be found in a 450-gram sample of the iron ore can be computed as follows:

100g of iron ore = 44g of iron

450 gram of iron ore = x g of iron

x(g) of iron = ( 44g of iron × 450 gram of iron ore) / 100g of iron ore

x(g) of iron =  198 grams of iron

Thus, there are 198 grams of iron in a 450-gram sample of the ore.

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5 0
1 year ago
(a) The original value of the reaction quotient, Qc, for the reaction of H2(g) and I2(g) to form HI(g) (before any reactions tak
Taya2010 [7]

Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

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Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} =  5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

 

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