Answer:
77.35 m / s
Ф = -17° from + X axis or 343° from + X axis
Explanation:
v1 = 75 m/s 25° east of north
v2 = 100 m/s 25° east of south
Write the velocities in vector form ,we get
Now add the velocity vectors to get the resultant of the velocities.
magnitude of resultant velocity is
= 77.35 m / s
The direction is Ф from X axis
Ф = -17° from + X axis or 343° from + X axis
Answer:
its speed is insignificant before the diver's speed change, so the result does not change
Explanation:
In this exercise of conservation of the momentum, the system is formed by the diver and the Earth
initial instant (before jumping)
p₀ = 0
final instant (after jumping)
= m v + M v²
how momentum is conserved
p₀ = p_{f}
0 = m v + M v²
v² = m / M v
since the mass of the Earth is M = 10²⁴ kg
its speed is insignificant before the diver's speed change, so the result does not change