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Sergio039 [100]
2 years ago
9

Guys I need the answer ASAP

Physics
1 answer:
kati45 [8]2 years ago
3 0

Answer:

cnbzdbhvhndjcn bvhdbvjsdhvjsbdjcbhkavwhe4w7334856743534685347856784687367856732346356675ygafjdbvc

Explanation:

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Miles and Joselin are riding a two person long board down an extremely dangerous hill while Chloe watches in horror and Talia in
saw5 [17]

Answer:

They will crash with the force of 6,000N

Explanation:

Force is equal to mass time acceleration. When we multiply 200 kg, the mass, and 30 m/s2, the acceleration, the answer is 6,000.

8 0
3 years ago
Why does the cannon move backward when the cannon ball is shot?
seropon [69]

Answer:

This came to mind

Explanation:

when a cannon fires (in real life or in the movies) have noticed that the cannon recoils, sliding backwards after the explosion. Again, a non-zero net force on the cannon changes its momentum.

6 0
2 years ago
Which graph shows the relationship between temperature, X, and kinetic energy, Y?
strojnjashka [21]
Answer: see the graph attached (straight line, passing through the origin and positive slope).


Justification:

1) Kinetic energy and temperature are in direct proportion. That means:

i)  Being kinetic energy y and temperature x: y α x

ii) That implies: y = kx,where k is the constant of proportionality.

iii) The graph is a line that passes through the origin and has positive slope k (k = y / x).

2) The proportional relationship between kinetic energy (KE) and temperature (T) is shown by the Boltzman law, which states:

Average KE = [3 / 2] KT, where K is Boltzman's constant, whose graph is of the form shown in the figure attached.

5 0
3 years ago
Read 2 more answers
When a certain amount of current flows through a resistor, it uses 3.00 W of power. If the current doubles, how much power will
asambeis [7]

Answer: 12

Explanation: Acellus

7 0
2 years ago
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car ent
Paha777 [63]

Answer:

0.8712 m/s²

Explanation:

We are given;

Velocity of first car; v1 = 33 m/s

Distance; d = 2.5 km = 2500 m

Acceleration of first car; a1 = 0 m/s² (constant acceleration)

Velocity of second car; v2 = 0 m/s (since the second car starts from rest)

From Newton's equation of motion, we know that;

d = ut + ½at²

Thus,for first car, we have;

d = v1•t + ½(a1)t²

Plugging in the relevant values, we have;

d = 33t + 0

d = 33t

For second car, we have;

d = v2•t + ½(a2)•t²

Plugging in the relevant values, we have;

d = 0 + ½(a2)t²

d = ½(a2)t²

Since they meet at the next exit, then;

33t = ½(a2)t²

simplifying to get;

33 = ½(a2)t

Now, we also know that;

t = distance/speed = d/v1 = 2500/33

Thus;

33 = ½ × (a2) × (2500/33)

Rearranging, we have;

a2 = (33 × 33 × 2)/2500

a2 = 0.8712 m/s²

3 0
2 years ago
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