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Afina-wow [57]
3 years ago
9

Could someone help me eliminate some of these answer choices?

Physics
2 answers:
Varvara68 [4.7K]3 years ago
8 0
In order to be processed by the brain, sound waves are converted into :
A. Electrical signal waves
In order to be carried out by our neurons, information has to be transferred as electrical wave through our brain nerves

hope this helps
Nuetrik [128]3 years ago
8 0

Explanation :

There are many types of waves like transverse waves or longitudinal waves. The sound is a longitudinal wave and light is a transverse wave. The longitudinal waves propagate in the form of compression and rarefaction.

Compression is the position where the particles are present in bulk i.e have maximum pressure or density. On the other hand, rarefaction is the position where the particles are far apart from each other.

Due to this pressure difference, noise is created into our eardrum that moves to the brain through the auditory nerve. This noise is in the form of electrical signal waves.

So, the sound waves are converted finally into electrical signal waves in order to be processed by the brain.

Hence, the correct option is (A).

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A planet has two
lozanna [386]
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.

<u>Moon #1:</u>  (1.262 days)² / (2.346 x 10^4 km)³

<u>Moon #2:</u>  (orbital period)² / (9.378 x 10^3 km)³

If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.

Cross multiply the proportion:

(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³

Divide each side by (2.346 x 10^4)³:

(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³

               =  0.1017 day²

Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.
7 0
3 years ago
Calcium-51 has a half-life of 4.5 days. Only 0.75 gram remains of a sample that was initially 12 grams. How old is the sample of
Over [174]
How many times did the original sample lose 50% of its radioactivity ?

-- Start with. . . . . . . . . . . . 12 grams.
-- Lose half of it once. . . . . . 6 grams left.
-- Lose half of it again . . . . . 3 grams left.
-- Lose half of it again . . . . . 1.5 grams left.
-- Lose half of it again . . . . . 0.75 gram left.

-- How many times did it lose half ?    4 times.

-- How long does it take to lose half ?  4.5 days. 
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-- How long did it take to lose half, 4 times ?

                                           (4 x 4.5 days) = 18 days .
6 0
3 years ago
Read 2 more answers
Explain why pulleys are in the lever family.
Aleks04 [339]

Answer:

The leverage or mechanical advantage of pulleys is less obvious, but you can "gang" multiple pulleys together into two sets (blocks) and run the ropes back and forth between the two sets to increase the number of lengths of rope running between them. One end of the rope is connected (fixed) to one of the blocks, and you get to pull on the other end after it is passed back and forth between the blocks of pulleys. This is sometimes called a block and tackle arrangement. With a hook on each side of the block set, you can move a heavy load much like levers do, by multiplying the force. You have to pull more rope just like you have to move a lever more on one side of the fulcrum as compared to the other. When you get all the rope pulled out that you can, you can not move the load anymore because you have become "two-blocked" which means the two blocks are together. Credits to: Moin Khan

3 0
3 years ago
A bus decreases its speed
eduard

Answer:

-6 km/h per minute

Explanation:

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Acceleration is the rate of change of the velocity of an object that is moving. This value is a result of all the forces that is acting on an object which is described by Newton's second law of motion. To determine acceleration, we need to know the initial velocity and the final velocity and the time elapsed. From the given values, we need t o calculate for the initial velocity. We use some kinematic equations. We do as follows:

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vf = v0 + at
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15 = v0 + 6a             (EQUATION 2)

Solving for v0 and a,
v0 = 5 m/s
a = 1.7 m/s^2
8 0
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