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Zolol [24]
4 years ago
15

You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the "oars") toward you, it moves a d

istance of 1.5 m in a time of 1.0 s. The readout on the display indicates that the average power you are producing is 82 W. What is the magnitude of the force that you exert on the handle?
Physics
1 answer:
tatyana61 [14]4 years ago
8 0

Answer:

54.67 N

Explanation:

The total energy produced is the product of power and time duration:

E = Pt = 82 * 1 = 82 J

Which is converted from work, product of forced extended over a displacement

W = E = Fs = F*1.5 = 82

F = 82 / 1.5 = 54.67 N

So the magnitude of the force exerting on the handle is 54.67 N

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By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and
puteri [66]

Answer:

14.8 kg

Explanation:

We are given that

m_1=43.7 kg

m_2=12.1 kg

g=9.8 m/s^2

a=\frac{1}{2}(9.8)=4.9 m/s^2

We have to find the mass of the pulley.

According to question

T_2-m_2 g=m_2 a

T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N

T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N

Moment of inertia of pulley=I=\frac{1}{2}Mr^2

(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)

Where \alpha=\frac{a}{r}

(177.87-214.13)=-\frac{1}{2}(4.9)M

-36.26=-\frac{1}{2}(4.9)M

M=\frac{36.26\times 2}{4.9}=14.8 kg

Hence, the mass of the pulley=14.8 kg

6 0
3 years ago
At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro
Feliz [49]

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

8 0
3 years ago
If a car travels 80 miles between 2 and 4 pm, then its velocity is close to 40 mph at 2 pm.
Alisiya [41]
The answer should be false because it doesnt say if the car is traveling at constant speed. The cars speed can be various so that in total for 2 hours that it travels it passes 80 miles. If however it actually traveled at constant speed than the answer is true.
3 0
3 years ago
What is an example of a concentric contraction
Genrish500 [490]

Answer:

an example is a bicep curl

Explanation:

A concentric contraction is a type of muscle activation that causes tension on your muscle as it shortens. As your muscle shortens, it generates enough force to move an object.

3 0
3 years ago
In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above
diamong [38]

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

Ymax = \frac{Vo^2}{2g}

Since we are told that Ya = 4Yb:

Ya =  \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}

Simplifying the equation:

Va^2 = 4*Vb^2

Va = 2*Vb

5 0
3 years ago
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