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Tatiana [17]
3 years ago
9

Would isotopes of the same element have the same number of electrons?

Chemistry
1 answer:
posledela3 years ago
8 0
No, isotopes would have a different number of electrons
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Hydrates that have a low vapor pressure and remove moisture from air are said to be ___. Question 8 options: effloresce hygrosco
-Dominant- [34]

Answer:

Hygroscopic

Explanation:

An hygroscopic substance is one that absorbs moisture from the atmosphere and becomes wet. Their ability to remove water from air is less than that of deliquescent substances. Most of the solid hygroscopic substances forms pasty substances and not solutions like the deliquescent compounds.

Examples are sodium trioxonitrate(v), copper(ii) oxide e.t.c

Efflorescence compounds gives off their water of crystallization to the atmosphere.

4 0
3 years ago
How is it possible for light to change genetic material?
Ivanshal [37]

Answer:

When light hits CRY2, it changes shape and binds to its natural partner protein, known as CIB1. When light shines on the cells, the CRY2 protein binds to CIB1, which is floating in the cell. CIB1 brings along a gene activator, which initiates transcription, or the copying of DNA into mRNA.

Explanation:

7 0
3 years ago
How many grams of NaOH are needed to make 500 mL of a 2.5 M NaOH solution
Veronika [31]
The number of grams  of NaOH  that are needed to make 500 ml of 2.5 M NaOH solution

calculate the number of moles =molarity x volume/1000

= 2.5 x 500/1000 = 1.25 moles

mass = moles  x molar mass of NaOH

= 1.25 x40= 50 grams of NaOH
4 0
4 years ago
What is public property​
Ne4ueva [31]

Answer:

ur mom

Explanation:

7 0
3 years ago
Read 2 more answers
What is the density of nitrogen gas if 0.186 g occupies a volume of 110 mL?
Anvisha [2.4K]

Answer:

d=1.69\times 10^{-3}\ g/mL

Explanation:

Given that,

Mass, m = 0.186 g

Volume occupies, V = 110 mL

We need to find the density of Nitrogen gas. The mass per unit volume is called density of an object. It is given by the formula as follows :

d=\dfrac{m}{V}\\\\d=\dfrac{0.186\ g}{110\ mL}\\\\=1.69\times 10^{-3}\ g/mL

So, the required density is 1.69\times 10^{-3}\ g/mL.

4 0
3 years ago
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