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Answer:
Boiling- 212° F melting- 32°F
Explanation:
Answer:
for the given reaction is -99.4 J/K
Explanation:
Balanced reaction: 
![\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]](https://tex.z-dn.net/?f=%5CDelta%20S%5E%7B0%7D%3D%5B1mol%5Ctimes%20S%5E%7B0%7D%28NH_%7B3%7D%29_%7Bg%7D%5D-%5B%5Cfrac%7B1%7D%7B2%7Dmol%5Ctimes%20S%5E%7B0%7D%28N_%7B2%7D%29_%7Bg%7D%5D-%5B%5Cfrac%7B3%7D%7B2%7Dmol%5Ctimes%20S%5E%7B0%7D%28H_%7B2%7D%29_%7Bg%7D%5D)
where 
represents standard entropy.
Plug in all the standard entropy values from available literature in the above equation:
![\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5E%7B0%7D%3D%5B1mol%5Ctimes%20192.45%5Cfrac%7BJ%7D%7Bmol.K%7D%5D-%5B%5Cfrac%7B1%7D%7B2%7Dmol%5Ctimes%20191.61%5Cfrac%7BJ%7D%7Bmol.K%7D%5D-%5B%5Cfrac%7B3%7D%7B2%7Dmol%5Ctimes%20130.684%5Cfrac%7BJ%7D%7Bmol.K%7D%5D%3D-99.4J%2FK)
So, for the given reaction is -99.4 J/K
1) 1 nm = 0.001 µm; one nanometer is equal to 0.001 (10⁻³) micrometer.
d(H) = 10 nm; diameter of hydrogen atom.
d(H) = 10 nm · 0.001 µm/nm.
d(H) = 0.01 µm = 10⁻² µm.
2) 1 nm = 10⁻⁹ m
; one meter is equal to 0.0000000001 (10⁻⁹) meter.
d(H) = 10 nm.
d(H) = 10 nm · 10⁻⁹ m/nm.
d(H) = 0.00000001 m = 10⁻⁸ m.
3) 1 nm = 10⁻⁶ mm
; one nanometer is equal to 0.000001 (10⁻⁶) millimeter.
d(H) = 10 nm · 10⁻⁶ mm/nm.
d(H) = 0.00001 mm = 10⁻⁵ mm.
