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3 years ago

What is the strength and direction of the electric field 3.560 cm?

1 answer:

8 0

Just treat the bead as a point charge.
E = kq/r^2, and E points away from the center of the sphere since the charge is positive.

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A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.680 Hz. The pendulum ha

sineoko [7]

Answer:

Therefore, the moment of inertia is:

$I=0.37 \: kgm^{2}$

Explanation:

The period of an oscillation equation of a solid pendulum is given by:

$T=2\pi \sqrt{\frac{I}{Mgd}}$ (1)

Where:

I is the moment of inertia
M is the mass of the pendulum
d is the distance from the center of mass to the pivot
g is the gravity

Let's solve the equation (1) for I

$T=2\pi \sqrt{\frac{I}{Mgd}}$

$I=Mgd(\frac{T}{2\pi})^{2}$

Before find I, we need to remember that

$T = \frac{1}{f}=\frac{1}{0.680}=1.47\: s$

Now, the moment of inertia will be:

$I=2*9.81*0.340(\frac{1.47}{2\pi})^{2}$

Therefore, the moment of inertia is:

$I=0.37 \: kgm^{2}$

I hope it helps you!

7 0

3 years ago

A projectile is fired at v 0 = 381.0 m/s at an angle of θ = 73.5 ∘ , with respect to the horizontal. Assume that air friction wi

Ipatiy [6.2K]

Answer:

Explanation:

velocity of projection, vo = 381 m/s

angle of projection, θ = 73.5°

The formula for the range is

$R=\frac{u^{2}Sin2\theta }{g}$

$R=\frac{381^{2}Sin147 }{9.8}$

R = 8067.4 m

Range in shorten by 34.1 %

So, the new range is

R' = 8067.4 - 34.1 x 8067.4/100

R' = 5316.4 m

5 0

3 years ago

What is the lens equation?

Strike441 [17]

The lens equation gives d relation between focal length, object distance n image distance.

1/f = 1/v + 1/u

seldon

7 0

3 years ago

Read 2 more answers

What is A common source of stress?

Oksanka [162]

Answer:

school, relashonships, etc.

Explanation:

5 0

3 years ago

Read 2 more answers

A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr

IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity $g=9.8m/sec^2$

Specific gravity of oil = 0.600

So density of oil $\rho =0.6\times 1000=600kg/m^3$

We know that absolute pressure is given by $P=P_0+\rho gh$ , here $P_0=1.01\times 10^5Pa$

So absolute pressure will be equal to $P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa$

So absolute pressure of the oil will be 102822.8 Pa

6 0

4 years ago