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ale4655 [162]
3 years ago
12

Use the drop-down menus to complete each sentence. The force applied to the physics cart is manipulated. This is the variable. T

he cart accelerates due to the force applied to the cart. Acceleration is therefore the variable. A "constant" is a parameter that stays the same regardless of the variables. One parameter of the cart that is held constant is the .
Physics
2 answers:
Nikitich [7]3 years ago
8 0

Answer:

the mass of the cart is held constant.

Explanation:

This can be solved by referring to the Newton's Second Law of Motion. Newton's Second Law of motion states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body, in the direction of force. Thus, both the force and the acceleration are directly proportional to each other. And the mass is kept constant during this process. As the formula derived by Newton's Second Law suggests that:

F = ma

It is clear from this equation that if the force and acceleration are variables, then the mass must be a constant.

<u>Hence, the mass of the cart is held constant.</u>

ELEN [110]3 years ago
6 0

Answer:

independent, dependent, applied force

Explanation:

i just did it on edgenuity

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Find the kinetic energy ofan electron that moves at half the speed of light to four significant digits.
Vlad1618 [11]

Answer:

Ke=electron kinetic energy=10.24*10^{33} J

Explanation:

The electron has a mass of 9.1*10^{-31} kg

The speed of light in a vacuum is a universal constant with the value 299 792 458 m / s (186 282,397 miles / s), although it is usually close to 3*10^{8} \frac{m}{s}

Kinetic energy (K) is the energy associated with bodies that are in motion, depends on the mass and speed of the body and is calculated using the formula:

K=\frac{1}{2} *m*v^{2}        Equation(1)

K=kinetic energy (J)

m =mass of the body (kg)

v= speed of the body(\frac{m}{s} )

for this problem We replace in the equation (1)

me=9.1*10^{-31} kg = electron mass

ve=1.5*10^{8} \frac{m}{s}=Half the speed of light

=electron speed

We replace in  the  equation (1) :

Ke=\frac{1}{2}*me*ve^{2}

Ke=\frac{1}{2} *9.1*10^{-31} *(1.5*10^{8} )^{2}

Ke=4.55*10^{-31} *(1.5)^{2} *(10^{8} )^{2}

Ke=10.24*10^{33} J

The energy kinetic of the electron is 10.24*10^{33} Joules

7 0
3 years ago
If the mass of an object is 35kg on venus what is its mass on the sun
REY [17]

Answer:

Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds

8 0
3 years ago
If an astronaut travels to different planets, which of the following planets will the astronaut’s weight be the same as on Earth
Nataly_w [17]
<h2>Astronaut travels to different planets - Option 4 </h2>

If an astronaut travels to different planets, none of the planets will the astronaut’s weight be the same as on Earth. On jupiter, weight will be more than the weight on earth. For instance if an astronaut has 100kg on earth then he will have 252 kg on jupiter.

On Mars, weight will be less than the weight on the earth. For instance, if an astronaut has 68 kg on earth then he will has 26 kg on mars. On Mercury, weight of an astronaut will be less than the weight on earth. Example if he has 68 kg on earth then he will have 25.7kg on mercury.

Hence, none of these planets the weight of astronaut will be same as on earth.

3 0
4 years ago
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An air bubble released by a remotely operated underwater vehicle, 120 m below the surface of a lake, has a volume of 1.40 cm3. T
Usimov [2.4K]

Answer:

17.7 cm^3

Explanation:

depth, h = 120 m

density of water, d = 1000 kg/m^3

V1 = 1.4 cm^3

P1 = P0 + h x d x g

P2 = P0

where, P0 be the atmospheric pressure

Let V2 be the volume of the bubble at the surface of water.

P0 = 1.01 x 10^5 Pa

P1 = 1.01 x 10^5 + 120 x 1000 x 9.8 = 12.77 x 10^5 Pa

Use

P1 x V1 = P2 x V2

12.77 x 10^5 x 1.4 = 1.01 x 10^5 x V2

V2 = 17.7 cm^3

Thus, the volume of bubble at the surface of water is 17.7 cm^3.

7 0
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Free body diagram is this correct?
lesya692 [45]

Answer:Yes that is correct

Explanation:

7 0
3 years ago
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