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koban [17]
4 years ago
15

Two astronauts in space with a baseball decide to play catch to pass the time. In the language of conservation of momentum, desc

ribe what happens to each astronaut as they start to toss the ball back and forth
Physics
2 answers:
IceJOKER [234]4 years ago
7 0

Answer:  Suppose that the first astronaut is still in place, then the full momentum of that astronaut is zero.

Now, when the astronaut throws the ball, now the ball has momentum, so the astronaut moves in the opposite direction to conserve the momentum (the movement of the arm also creates a response in the body of the astronaut)

(all of this can be explained also by the third Newton's law, for example, the astronaut that accelerates the baseball also experiences a force that the baseball does in him)

Usually, in the earth, the force of gravity keeps the players in place, but in the space, this is not the case, so the tiny force that the ball does in the astronaut is enough to accelerate the astronaut.

It is the same for the other one, the ball comes with a little bit of momentum, so when he catches the ball, the momentum must be conserved, so the astronaut will move in the same direction that the ball was moving.

Anna35 [415]4 years ago
4 0
As the first astronaut throws the ball, lets assume it goes with v velocity and the mass of the ball be m
the momentum comes out be mv, thus to conserve that momentum the astronaut will move opposite to the direction of the ball's motion with the velocity mv/M (where M is the mass of the astronaut).
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A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, \rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}

Change in Pressure in the tank, \Delta P = 7.28\ mmHg

Density of the mercury, \rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

\Delta P = 7.28\ times 133.332 = 970.656\ Pa

Also,

\Delta P = \rho_{o} gh

where

g = acceleration due to gravity

h = height of the fluid level

970.656 = 900\times 9.8\times h

h = 0.11 m

Now, if mercury is used:

\Delta P = \rho_{m} gh

970.656 = 13600\times 9.8\times h

h = 0.00728 m = 7.28 mm

3 0
4 years ago
If you had an unlimited amount of mass to hang, what would be the range of possible accelerations for the system?
LenaWriter [7]

Answer:

The entire cart/hanging mass system follows the same law, ΣF = ma. This means that plotting force vs. acceleration yields a linear relationship (of the form y = mx).

3 0
3 years ago
A ball is thrown upward. After reaching a
Triss [41]

Answer:

9.0 m/s

Explanation:

The problem can be solved by using the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity

t is the time

When the ball reaches the maximum height, the velocity becomes zero. If we consider this as initial point of the motion, we can write

u = 0

The time it takes for the ball to go down from the maximum heigth to the ground is half the total time, so

t=\frac{1.84s}{2}=0.92 s

And solving the formula for v, we find the final velocity:

v=0+(-9.8)(0.92)=-9.0 m/s

So, the final speed is 9.0 m/s.

3 0
4 years ago
Calcium-51 has a half-life of 4.5 days. Only 0.75 gram remains of a sample that was initially 12 grams. How old is the sample of
marysya [2.9K]
 The answer is 18 grams.

12 grams.divided by 2= 6 grams divided by 2=3 gramsdivided by 2= 1.5 gramsdivided by 2= 0.75 gram 
4 times it is being halfed4.5 day it takes to lose the half
                                                     So, (4 x 4.5 days) = 18 days .
Read 
9 0
4 years ago
Read 2 more answers
A 946.4 kg ( 2083 lb ) car is moving at 14.8 m / s ( 33.0 mph ) . Calculate the magnitude of its momentum.
IgorLugansk [536]

Answer:

14009. 72 kgms^-1

Explanation:

Momentum is the product of an objects mass and velocity

7 0
4 years ago
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