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koban [17]
3 years ago
15

Two astronauts in space with a baseball decide to play catch to pass the time. In the language of conservation of momentum, desc

ribe what happens to each astronaut as they start to toss the ball back and forth
Physics
2 answers:
IceJOKER [234]3 years ago
7 0

Answer:  Suppose that the first astronaut is still in place, then the full momentum of that astronaut is zero.

Now, when the astronaut throws the ball, now the ball has momentum, so the astronaut moves in the opposite direction to conserve the momentum (the movement of the arm also creates a response in the body of the astronaut)

(all of this can be explained also by the third Newton's law, for example, the astronaut that accelerates the baseball also experiences a force that the baseball does in him)

Usually, in the earth, the force of gravity keeps the players in place, but in the space, this is not the case, so the tiny force that the ball does in the astronaut is enough to accelerate the astronaut.

It is the same for the other one, the ball comes with a little bit of momentum, so when he catches the ball, the momentum must be conserved, so the astronaut will move in the same direction that the ball was moving.

Anna35 [415]3 years ago
4 0
As the first astronaut throws the ball, lets assume it goes with v velocity and the mass of the ball be m
the momentum comes out be mv, thus to conserve that momentum the astronaut will move opposite to the direction of the ball's motion with the velocity mv/M (where M is the mass of the astronaut).
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A particle hangs from a spring and oscillates with a period of 0.2s.If the mass-spring system remained at rest, by how much woul
photoshop1234 [79]

Answer:

The distance the mass would stretch it is    x = 0.00992948

The correct option is A

Explanation:

From the question we are told that

           The period of the slit is T = 0.2s

           The acceleration due to gravity is g =9.8 m/s^2

Generally the period is mathematically represented as

                     T = 2 \pi \sqrt{\frac{m}{k} }

          Whee m is the particle and k is the spring constant

        making \frac{m}{k} the subject

                        \frac{m}{k}  = [\frac{T}{2 \pi} ]^2

The weight on the particle is related to the force stretching the spring by this mathematical relation

               W = F_s

              mg = kx

where x is the length by which the spring is stretched

          \frac{m}{k}  = \frac{x}{g}

Substituting the equation above for \frac{m}{k}

            [\frac{T}{2 \pi} ]^2 = \frac{x}{g}

making x the subject

              x = g [\frac{T}{2 \pi} ]

Substituting the value

            x = 9.8 * [\frac{0.2}{2 * 3.142} ]^2

            x = 0.00992948

6 0
3 years ago
Read 2 more answers
What is it asking MathPhys im sorry i dont know but i tried teaching myself physics but i cant
RSB [31]

Answer:

The puck B remains at the point of collision.

Explanation:

This is an elastic collision, so both momentum and energy are conserved.

The mass of both pucks is m.

The velocity of puck B before the collision is vb.

The velocity of puck A and B after the collision is va' and vb', respectively.

Momentum before = momentum after

m vb = m vb' + m va'

vb = vb' + va'

Energy before = energy after

½ m vb² = ½ m vb'² + ½ m va'²

vb² = vb'² + va'²

Substituting:

(vb' + va')² = vb'² + va'²

vb'² + 2 va' vb' + va'² = vb'² + va'²

2 va' vb' = 0

va' vb' = 0

We know that va' isn't 0, so:

vb' = 0

The puck B remains at the point of collision.

6 0
3 years ago
.physics wave. Please don't dare to answer irrelevant
MAVERICK [17]

Answer:

1a) 857143 m

1b) 414 m

2a)

2b)

3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.

Explanation:

Question 1a)

Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.

[ λ = v / f ] wavelength = <u>v</u>elocity of the wave / <u>f</u>requency of the wave in Hz.

Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.

Anything to the negative power is reciprocated. i.e ms^-1 = m/s.

The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m

Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1

Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz

The wavelength is found using the same

formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m

Question 2a)

Question 2b)

Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.

Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =

Question 4)

3 0
3 years ago
What is the wavelength of the radio waves from an FM station operating at a frequency of 99.5 MHz
ser-zykov [4K]

Answer:

Wavelength, \lambda=3.01\ m

Explanation:

It is given that,

Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz

We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :

c=f\lambda

\lambda=\dfrac{c}{f}{

c = speed of light

\lambda=\dfrac{3\times 10^8\ m/s}{99.5\times 10^6\ Hz}

\lambda=3.01\ m

So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.

3 0
3 years ago
What voltage would produce a current of 100amps through an aluminum wire assuming that the re sistance of the wire is3.44×10-4 o
agasfer [191]
V = IR

I = current
R = resistance

Voltage = 100 * (3.44x 10^-4) = do the calculation

Hope this helps
8 0
2 years ago
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