Answer:
The distance the mass would stretch it is 
The correct option is A
Explanation:
From the question we are told that
The period of the slit is 
The acceleration due to gravity is 
Generally the period is mathematically represented as

Whee m is the particle and k is the spring constant
making
the subject
The weight on the particle is related to the force stretching the spring by this mathematical relation


where x is the length by which the spring is stretched

Substituting the equation above for 
![[\frac{T}{2 \pi} ]^2 = \frac{x}{g}](https://tex.z-dn.net/?f=%5B%5Cfrac%7BT%7D%7B2%20%5Cpi%7D%20%5D%5E2%20%3D%20%5Cfrac%7Bx%7D%7Bg%7D)
making x the subject
![x = g [\frac{T}{2 \pi} ]](https://tex.z-dn.net/?f=x%20%3D%20g%20%5B%5Cfrac%7BT%7D%7B2%20%5Cpi%7D%20%5D)
Substituting the value
![x = 9.8 * [\frac{0.2}{2 * 3.142} ]^2](https://tex.z-dn.net/?f=x%20%3D%209.8%20%2A%20%5B%5Cfrac%7B0.2%7D%7B2%20%2A%203.142%7D%20%5D%5E2)

Answer:
The puck B remains at the point of collision.
Explanation:
This is an elastic collision, so both momentum and energy are conserved.
The mass of both pucks is m.
The velocity of puck B before the collision is vb.
The velocity of puck A and B after the collision is va' and vb', respectively.
Momentum before = momentum after
m vb = m vb' + m va'
vb = vb' + va'
Energy before = energy after
½ m vb² = ½ m vb'² + ½ m va'²
vb² = vb'² + va'²
Substituting:
(vb' + va')² = vb'² + va'²
vb'² + 2 va' vb' + va'² = vb'² + va'²
2 va' vb' = 0
va' vb' = 0
We know that va' isn't 0, so:
vb' = 0
The puck B remains at the point of collision.
Answer:
1a) 857143 m
1b) 414 m
2a)
2b)
3) the medium of air has a wavelength of 0.334 m, the medium of water has a wavelength of 1.493 m, and the medium of 5.130 m.
Explanation:
Question 1a)
Given the velocity/speed, and frequency of the wave, the length can be calculated using these two quantites.
[ λ = v / f ] wavelength = <u>v</u>elocity of the wave / <u>f</u>requency of the wave in Hz.
Since 3 × 10^8 × ms^-1 is the velocity, and 350Hz is the frequency.
Anything to the negative power is reciprocated. i.e ms^-1 = m/s.
The wavelength is 300000000m/350Hz = 857142.8571428..... m ≈ 857143 m
Question 1b) Given that the frequency of the second wave in water is 1% of the first wave, and the speed of the second wave is 1450ms^-1
Therefore the second wave has a frequency of 1% of 3.5 = 350/100 Hz = 3.5 Hz
The wavelength is found using the same
formula: wavelength = 1450m/3.5Hz = 414.2857142857.... m ≈ 414 m
Question 2a)
Question 2b)
Question 3) Remember, the speed of sound of the medium = frequency of the medium × wavelength of the medium.
Therefore the wavelength of the medium = speed of sound of the medium / frequency of the medium. This has a similar correlation to the wavelength formula. We are given that all these mediums have a frequency of 1KHz = 1000Hz, where So the wavelength of each medium =
Question 4)
Answer:
Wavelength, 
Explanation:
It is given that,
Frequency, f = 99.5 MHz = 99.5 × 10⁶ Hz
We need to find the wavelength of the radio waves from an FM station operating at above frequency. The relationship between the frequency and the wavelength is given by :


c = speed of light


So, the wavelength of the radio waves from an FM station is 3.01 m. Hence, this is the required solution.
V = IR
I = current
R = resistance
Voltage = 100 * (3.44x 10^-4) = do the calculation
Hope this helps