Answer:
0.054 M
Explanation:
1 mol NaHSO4 -> 120 g
x ->13 g
x= 0.108 mol NaHSO4
M= mol solute/ L solution
M= 0.108 mol NaHSO4/ 2.00L
M= 0.054 M
Answer:
The answer to your question is: 3000 cm
Explanation:
30 meters long to cm
We can use a rule of three to solve it
We know that 1 meter ------------------ 100 cm
30 meters ---------------- x
x = 30(100)/1 = 3000 cm
Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Solution : Given,
Mass of Cu = 300 g
Molar mass of Cu = 63.546 g/mole
Molar mass of 
= 183.511 g/mole
- First we have to calculate the moles of Cu.
The moles of Cu = 4.7209 moles
From the given chemical formula, we conclude that the each mole of compound contain one mole of Cu.
So, The moles of Cu = Moles of = 4.4209 moles
- Now we have to calculate the mass of .
Mass of = Moles of × Molar mass of = 4.4209 moles × 183.511 g/mole = 866.337 g
Mass of = 866.337 g = 0.8663 Kg (1 Kg = 1000 g)
Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Answer:
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Answer :
Example of polar covalent molecules H-O-H(water), ammonia
Explanation:
The presence of intermolecular Hydrogen bonding makes the boiling point of water unexpectedly high, and the polar covalent nature makes it dissolve polar solute/compound
