Question

4786 joules fer transferred to an 89.0 gram sample of a unknown material with an initial temperature of 23.0°C what is the specific heat of the measure in the final temperature is 89.5°C

Answer 1

Specific heat formula is Q=M*C*ΔT
Q is amount of energy (4786 J)
M is mass (89.0 g)
C is specific heat (unknown, answer will be in J/gºC)
ΔT is the change in temp (89.5-23.0=66.5ºC)
Let's plug it in.
4786=89.0(C)(66.5)
4786=5918.5(C)
/5918.5  
C=.8086508406 J/gºC
with sig figs...
C=.809 J/gºC

Answer 2

Answer:

0.8087 C J/g oC

Explanation:

4786 J = 89.0 g x C x (89.5 C- 23.0 C)  

4786 J = 6185.5 gC

0.8087 C J/g oC

0.809 C J/g C (sig figs)